在数列{an}中,a1=1,2a(n+1)=(1+1/n)^2*an,(1)证明数列{an/n^2}是等比数列,并求{an}的通项公式(2)令bn=a(n+1)-1/2an,求数列{bn}的前n项和Sn;(3)求数列{an}的前n项和Tn
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![在数列{an}中,a1=1,2a(n+1)=(1+1/n)^2*an,(1)证明数列{an/n^2}是等比数列,并求{an}的通项公式(2)令bn=a(n+1)-1/2an,求数列{bn}的前n项和Sn;(3)求数列{an}的前n项和Tn](/uploads/image/z/1767815-71-5.jpg?t=%E5%9C%A8%E6%95%B0%E5%88%97%7Ban%7D%E4%B8%AD%2Ca1%3D1%2C2a%28n%2B1%29%3D%281%2B1%2Fn%29%5E2%2Aan%2C%EF%BC%881%EF%BC%89%E8%AF%81%E6%98%8E%E6%95%B0%E5%88%97%7Ban%2Fn%5E2%7D%E6%98%AF%E7%AD%89%E6%AF%94%E6%95%B0%E5%88%97%2C%E5%B9%B6%E6%B1%82%7Ban%7D%E7%9A%84%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F%EF%BC%882%EF%BC%89%E4%BB%A4bn%3Da%28n%2B1%29-1%2F2an%2C%E6%B1%82%E6%95%B0%E5%88%97%7Bbn%7D%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8CSn%3B%283%29%E6%B1%82%E6%95%B0%E5%88%97%7Ban%7D%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8CTn)
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