化简(1+sin2A+cos2A)(sinA-cosA)/根号(2+2cos2A本来原题2A是A,A是A/2的,嫌输入麻烦,擅自改了...不要被迷惑....
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![化简(1+sin2A+cos2A)(sinA-cosA)/根号(2+2cos2A本来原题2A是A,A是A/2的,嫌输入麻烦,擅自改了...不要被迷惑....](/uploads/image/z/1801962-18-2.jpg?t=%E5%8C%96%E7%AE%80%EF%BC%881%2Bsin2A%2Bcos2A%EF%BC%89%EF%BC%88sinA-cosA%EF%BC%89%2F%E6%A0%B9%E5%8F%B7%EF%BC%882%2B2cos2A%E6%9C%AC%E6%9D%A5%E5%8E%9F%E9%A2%982A%E6%98%AFA%2CA%E6%98%AFA%2F2%E7%9A%84%2C%E5%AB%8C%E8%BE%93%E5%85%A5%E9%BA%BB%E7%83%A6%2C%E6%93%85%E8%87%AA%E6%94%B9%E4%BA%86...%E4%B8%8D%E8%A6%81%E8%A2%AB%E8%BF%B7%E6%83%91....)
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化简(1+sin2A+cos2A)(sinA-cosA)/根号(2+2cos2A本来原题2A是A,A是A/2的,嫌输入麻烦,擅自改了...不要被迷惑....
化简(1+sin2A+cos2A)(sinA-cosA)/根号(2+2cos2A
本来原题2A是A,A是A/2的,嫌输入麻烦,擅自改了...不要被迷惑....
化简(1+sin2A+cos2A)(sinA-cosA)/根号(2+2cos2A本来原题2A是A,A是A/2的,嫌输入麻烦,擅自改了...不要被迷惑....
(1+sin2A+cos2A)(sinA-cosA)/根号(2+2cos2A)
=2cosa(sina+cosa)(sina-cosa)/|2cosa|
=-cos2a或cos2a
=(1+sin2A+2cosA的平方-1)(sinA-cosA)/根号【2+2(2cosA的平方-1)】
=(2sinAcosA+2cosA的平方)(sinA-cosA)/2cosA(假设其大于0)
=(sinA+cosA)(sinA-cosA)
=-cos2A
化简:(1+sin2a-cos2a)/(1+sin2a+cos2a)
化简(1+cos2a+sin2a)/(1-cos2a+sin2a)
化简:(1+sin2a+cos2a)/(1+sin2a-cos2a)
(1-cos2a)/sin2a化简
化简 1-cos2a/sin2a
化简2sin2a/1+cos2a*cos2/cos2a
化简 [(tan2a-1/tan2a)/sin2a-cos2a]+1/cos2a-1/sin2a
化简(sin2a+cos2a-1)(sin2a-cos2a+1)除以sin4a
化简(sin2a+cos2a-1)(sin2a-cos2a+1)除以sin4a
化简:(1+cos2a)/sin2a-sin2a/(1-cos2a)=
(1-sin2a+cos2a)/(1+sin2a-cos2a
1.化简[2sin2a/(1+cos2a)]*1/tana
化简:sin2a/sin(π+a)+cos2a+1/cosa化简[:(sin2a)/(sin(π+a))]+[(cos2a+1)/cosa]
[2(cosa)2/sin2a]*[(1-cos2a)/cos2a]化简
化简[2sin2a/(1+cos2a)]*(cos^2a/cos2a)
sin2a/(1+cos2a)-cosa/(1+cosa)化简
化简:(sin2a/1+cos2a)*(COSa/1+cosa)
(sin2a+cos2a+1)/(1+tana)化简