1.化简[2sin2a/(1+cos2a)]*1/tana
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/13 10:43:29
![1.化简[2sin2a/(1+cos2a)]*1/tana](/uploads/image/z/5499974-38-4.jpg?t=1.%E5%8C%96%E7%AE%80%5B2sin2a%2F%281%2Bcos2a%EF%BC%89%5D%2A1%2Ftana)
xN@_c-MHVN\Jcy bT*@0॥ޅt
.zd/7Ϲ§Z6K|r
zg.k_v"\FklCDKV]UȔR6,ӕTL%xܾf@8{Y\n
Յ|>&Vowx8pswNaSFsx?d2èiQ ZS|d*;=׃*SǴu/i
1.化简[2sin2a/(1+cos2a)]*1/tana
1.化简[2sin2a/(1+cos2a)]*1/tana
1.化简[2sin2a/(1+cos2a)]*1/tana
原式可化为(2*2*sina*cosa)/[(cosa)^2+(sina)^2+(cosa)^2-(sina)^2]*cosa/sina
继续化简得2*sina/cosa*cosa/sina=2
sin2a=2sina*cosa cos2a=2cosa的平方—1 tana=sina/cosa 把这几个带入可以化简得结果为2 书写不太方便 应该可以看懂吧
化简2sin2a/1+cos2a*cos2/cos2a
化简:(1+sin2a+cos2a)/(1+sin2a-cos2a)
(1-cos2a)/sin2a化简
化简 1-cos2a/sin2a
[2(cosa)2/sin2a]*[(1-cos2a)/cos2a]化简
化简[2sin2a/(1+cos2a)]*(cos^2a/cos2a)
1.化简[2sin2a/(1+cos2a)]*1/tana
化简 [(tan2a-1/tan2a)/sin2a-cos2a]+1/cos2a-1/sin2a
化简(sin2a+cos2a-1)(sin2a-cos2a+1)除以sin4a
化简(sin2a+cos2a-1)(sin2a-cos2a+1)除以sin4a
化简:(1+sin2a-cos2a)/(1+sin2a+cos2a)
化简(1+cos2a+sin2a)/(1-cos2a+sin2a)
化简:(1+cos2a)/sin2a-sin2a/(1-cos2a)=
(1-sin2a+cos2a)/(1+sin2a-cos2a
化简[ (1+cos2a)/sin2a ] · 2tan a要详解
化简(1+cos2a)/3sin2a · 2sin^2a/cos2a
化简2cos^a/sin2a乘1-cos2a/cos2a的结果
求证:2(sin2a+1)/(1+sin2a+cos2a)=tana+1