3(m^2+mn)-4(mn-2m^2n)+mn
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3(m^2+mn)-4(mn-2m^2n)+mn
3(m^2+mn)-4(mn-2m^2n)+mn
3(m^2+mn)-4(mn-2m^2n)+mn
3(m^2+mn)-4(mn-2m^2n)+mn
=3m²+3mn-4mn+2m²n+mn
=3m²+2m²n
=m²(3+2n)
3(m^2n+mn)-4(mn-2m^2n)+mn.要有过程
已知m-n=2,mn=1,求多项式(-2mn+2mn+3n)-(3mn+2n-2m)-(m+4n+mn)的值
已知m-n=2,mn=1,求多项式(-2mn+2mn+3n)-(3mn+2n-2m)-(m+4n+mn)的值
3(m^2+mn)-4(mn-2m^2n)+mn
(5mn-2m+3n)+(-7m-7mn)
(5mn-2m+3n)+(-7m-7mn)
2mn[(2mn)^2-3n(mn+m^2*n)-mn^2]计算
2mn[(2mn)²-3n(mn+m²n)-mn²
因式分解m^3-2m^2n+mn^2-4m^2+4mn+4m
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