lg5^2+2/3lg8+lg5*lg20+lg^2
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/18 17:26:11
xN
~<!|.^$F"˾XXK AْgIb*4a;W0qPO[#]?-v^LC^}yKӈ
GH
lg5^2+2/3lg8+lg5*lg20+lg^2
lg5^2+2/3lg8+lg5*lg20+lg^2
lg5^2+2/3lg8+lg5*lg20+lg^2
=2lg5+2/3*lg2³+lg5(lg2+lg10)+lg²2
=2lg5+2lg2+lg5lg2+lg5+lg²2
=2(lg5+lg2)+lg2(lg5+lg2)+lg5
=2+lg2+lg5
=2+1
=3
lg5^2+2/3lg8+lg5*lg20+lg2^2
lg5^2+lg8^2/3+lg5*lg20+(lg2)^2=?
(lg5)平方+2/3lg8+lg5乘lg20+(lg2)平方
3lg2+2lg5+lg5乘以lg8怎样算
lg5²+2/3lg8+lg5*lg20+(lg2)²
lg5²+2/3lg8+lg5×lg20+(lg2)²
lg2+lg5=?1-lg2=?1-lg5=?2lg5+2/3lg8+lg5*lg20+(lg2)2=?
lg5^2+2/3lg8+lg5*lg20+(lg2)^2 lg5*lg20怎么办啊
(lg2)^3+(lg5)^3+lg5*lg8=(lg2+lg5)[(lg2)^2-lg2*lg5+(lg5)^2]+lg5*lg2^3=1[(lg2)^2-lg2*lg5+(lg5)^2]+3lg5*lg2=(lg2)^2+(lg5)^2+2lg5*lg2=(lg2+lg5)^2=1网上看了看答案,可是第一步没有看懂.求得出第一步的过程,
对数lg2*lg5=?2lg(5)+2/3 lg8+lg5*lg20+lg2 =lg5^2+lg8^(2/3)+lg5*(lg4+lg5)+lg2 =lg100+lg5+2lg2*lg5+lg2 =2+(lg5+lg2) =2+1 =3 第二个等号lg5*(lg4+lg5)为什么=lg5+2lg2*lg5
lg5(2)+2/3lg8+lg5*lg2+(lg2)^2
计算:(lg2)2+3lg5+lg5(1+lg2)+lg8+log2(5)log5(4)
化简[(1-lg5)^2+lg2乘lg5]/lg8
lg25+2/3lg8+lg5*lg20+(lg2)^2
(lg2)^2+lg25+2/3lg8+lg5*lg20=?
lg25+2/3lg8+lg5*lg20+(lg2)^2=?
lg25+(2/3)lg8+lg5.lg20+(lg2)^2
lg25+(2/3)lg8+lg5.lg20+(lg2)^2=?