在三棱锥S-ABC中,△ABC是边长为4的正三角形,平面SAC⊥平面ABC,SA=SC=2根号3,M.N为AB的中点.(1)证明:AC⊥SB;(2)求二面角N-CM-B的大小;(3)求点B到平面SCM的距离.
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![在三棱锥S-ABC中,△ABC是边长为4的正三角形,平面SAC⊥平面ABC,SA=SC=2根号3,M.N为AB的中点.(1)证明:AC⊥SB;(2)求二面角N-CM-B的大小;(3)求点B到平面SCM的距离.](/uploads/image/z/1838031-15-1.jpg?t=%E5%9C%A8%E4%B8%89%E6%A3%B1%E9%94%A5S-ABC%E4%B8%AD%2C%E2%96%B3ABC%E6%98%AF%E8%BE%B9%E9%95%BF%E4%B8%BA4%E7%9A%84%E6%AD%A3%E4%B8%89%E8%A7%92%E5%BD%A2%2C%E5%B9%B3%E9%9D%A2SAC%E2%8A%A5%E5%B9%B3%E9%9D%A2ABC%2CSA%3DSC%3D2%E6%A0%B9%E5%8F%B73%2CM.N%E4%B8%BAAB%E7%9A%84%E4%B8%AD%E7%82%B9.%EF%BC%881%EF%BC%89%E8%AF%81%E6%98%8E%EF%BC%9AAC%E2%8A%A5SB%EF%BC%9B%EF%BC%882%EF%BC%89%E6%B1%82%E4%BA%8C%E9%9D%A2%E8%A7%92N-CM-B%E7%9A%84%E5%A4%A7%E5%B0%8F%EF%BC%9B%EF%BC%883%EF%BC%89%E6%B1%82%E7%82%B9B%E5%88%B0%E5%B9%B3%E9%9D%A2SCM%E7%9A%84%E8%B7%9D%E7%A6%BB.)
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