【急】等腰三角形的轴对称性如图,在△ABC中,∠ACB=90°,高CD和角平分线AE交于点F,EH⊥AB于点H,那么CF=EH吗?请说明理由.
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/14 13:49:51
![【急】等腰三角形的轴对称性如图,在△ABC中,∠ACB=90°,高CD和角平分线AE交于点F,EH⊥AB于点H,那么CF=EH吗?请说明理由.](/uploads/image/z/1852460-44-0.jpg?t=%E3%80%90%E6%80%A5%E3%80%91%E7%AD%89%E8%85%B0%E4%B8%89%E8%A7%92%E5%BD%A2%E7%9A%84%E8%BD%B4%E5%AF%B9%E7%A7%B0%E6%80%A7%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E2%96%B3ABC%E4%B8%AD%2C%E2%88%A0ACB%3D90%C2%B0%2C%E9%AB%98CD%E5%92%8C%E8%A7%92%E5%B9%B3%E5%88%86%E7%BA%BFAE%E4%BA%A4%E4%BA%8E%E7%82%B9F%2CEH%E2%8A%A5AB%E4%BA%8E%E7%82%B9H%2C%E9%82%A3%E4%B9%88CF%3DEH%E5%90%97%3F%E8%AF%B7%E8%AF%B4%E6%98%8E%E7%90%86%E7%94%B1.)
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