若cos(α-π/6)+sinα=4√3/5,则sin(α+7π/6)的值是

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/30 10:31:45
若cos(α-π/6)+sinα=4√3/5,则sin(α+7π/6)的值是
x){ѽ49XF fřy6ښ

若cos(α-π/6)+sinα=4√3/5,则sin(α+7π/6)的值是
若cos(α-π/6)+sinα=4√3/5,则sin(α+7π/6)的值是

若cos(α-π/6)+sinα=4√3/5,则sin(α+7π/6)的值是
展开cos(α-π/6)+sinα
=√3/2cosα+1/2sinα+sinα=√3/2cosα+3/2sinα=4√3/5
两边同除√3,得1/2cosα+√3/2sinα=4/5,
合并,sin(α+π/6)=4/5
看要求的式子是sin(α+7π/6)=-sin(α+π/6)=-4/5.

已知sinα+cosα=4/5且3π/22,若sinα+sinβ+sinγ=0,cosα+cosβ+cosγ=0,则cos(α-β)的值 利用和差角公式化简 (2)sin(π/3+α)+sin(π/3-α)(2)sin(π/3+α)+sin(π/3-α)(3)cos(π/4+α)-cos(π/4-α)(4)cos(60°+α)+cos(60°-α)(5)sin(α-β)cosβ+cos(α-β)sinβ(6)cos(α+β)cosβ+sin(α+β)sinβ 若方程12x²+πx-12x=0的两的根分别是α,β,则cosαcosβ-√3sinαcosβ-√cosαsinβ-sinαsinβ= 化简:sin(π/4-α)cos(π/3-α)-cos(π/6+α)sin(π/4+α)= 若sinα+sin^2α=1,则cos^2α+cos^4α+cos^6α=? 求值:(tan10°-√3)×cos10°/sin50° 求证:[sin(2α+β)]/sinα- 2cos(α+β)=sinβ/cosα 化简cosθ+cos(θ+2π/3)+cos(θ+4π/3) 证明:sin(α+β)sin(α-β)=sin^2α-sin^2β 已知(sinα-cosα)/(sinα+cosα)=1/3,则cos^4(π/3+α)-cos^4(π/6-α)的值为答案好像是(3-4√3)/10 设角a=-35π/6,则2sin(π+α)cos(π-α)-cos(π+α)/ 1+sin^2α+sin(π-α)-cos^2(π+α)sina=sin(-35π/6)=sin(-6π+π/6)=1/2 cosα=根号3/22sin(π+α)cos(π-α)-cos(π+α)/ [1+sin^2α+sin(π-α)-cos^2(π+α)]=2(-sinα)(-cosα)+cosα/[1+sin² 若cos(α+π/6)-sinα=(3√3)/5,则cos(α+π/3)=___ 若(4sinα-2cosα)/(5cosα+3sinα)=10,且α∈(-π/2,0)则cosα值为 已知0<α<π/2,且3sinα=4cosα求(sin^2α+2sinαcosα)/(3cos^2α-1)求cos^2α+sinαcosα 已知tan(α+π/4)=3,计算2sinαcosα+6cos方α-3/5cos方α-6sinαcosα-5sin方α 若sinα+cosβ=2/3 cosα+cosβ=5/6求cos(α-β) 已知6sin²α+sinαcosα-2cos²α=0,α∈(π/2,π),求值1).(sinα-3cosα)/(sinα-cosα);2).sinαcosα-sin²α;3).sin²α-3cosαsinα-2 证明 三角函数 不等式用恒等式2cosAsinB=sin(A+B)-sin(A-B)证明:2[cosβ+cos(β+2α)+cos(β+4α)]sinα=sin(β+5α)-sin(β-α).推导出:cosβ+cos(β+2π/3)+cos(β+4π/3)=0.解不等式:√(x+5)≤1+|x|.【一共有两题啊!】 1.化简根号2cos x - 根号6sin x2.已知sin(α-β)cosα-cos(β-α)sinα=3/5,β是第三象限角,求sin(β+5π/4)的值.3.化简sin(α-β)sin(β-λ)-cos(α-β)cos(λ-β) 已知sinα+sinβ+sinγ=0,cosα+cosβ+cosγ=0若α,β,γ∈[0,4π/3],求sin(α+β+γ)的值 已知sin(3π+α)=2cos(α-4π)求cos(π/2 -α)+5sin(π/2 +α)/2cos(π+α)-sin(-α)