2x²+xy-y²-4x+5y-6 因式分解
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/28 21:53:59
![2x²+xy-y²-4x+5y-6 因式分解](/uploads/image/z/1990149-69-9.jpg?t=2x%26sup2%3B%2Bxy-y%26sup2%3B-4x%2B5y-6+%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3)
x)3P+.-0֮ԭ0uM*M+u^tOӎ$XΆd
`tThWөaT[ 7kVm7,65PH~qAb6`)+6>];Ovxy=zGeCs{ tH*45te5DA%:PtVl*ImdltzX[
d-T?H
L._yTDGH!I ?
2x²+xy-y²-4x+5y-6 因式分解
2x²+xy-y²-4x+5y-6 因式分解
2x²+xy-y²-4x+5y-6 因式分解
2x^2+xy-y^2-4x+5y-6
=(x+y)(2x-y)-4x+5y-6
=(x+y)(2x-y)+2(x+y)-6x+3y-6
=(x+y)(2x-y+2)-3(2x-y+2)
=(2x-y+2)(x+y-3)
用十字相乘法:原式=2x²+﹙y-4﹚x-﹙y²-5y+6﹚=2x²+[2﹙y-3﹚-﹙y-2﹚]x-﹙y-2﹚﹙y-3﹚=[2x-﹙y-2﹚][x+﹙y-3﹚]=﹙2x-y+2﹚﹙x+y-3﹚
用双十字相乘法,得(2x-y+2)(x+y-3)
H HTR GF GF
x²-2xy+y²-9
若x²+xy-2y²=0,则x²+3xy+y²/x²+y²
x²+xy-2y²=0则x²+3xy+y²/x²+y²
因式分解 x²-2xy+y²-z²
计算:4xy²-3x²y-{3x²y-[2xy²-4x²y+2(x²y-2xy²)]急
x²-4y²/x²+2xy+y²÷x+2y/2x²+2xy
计算x²-x/x²×x/1-x和x²-4y²/x²+2xy+y²÷x+2y/x²+xy
x²-y²+6x+9分之x²+y²-9-2xy
因式分解 x²-XY-2y²-X-Y
x²+xy-2y²-x+7y-6
(xy-x²)÷[(x²-2xy+y²)÷xy]*[(x-y)÷x²]
6x²-xy-15y²=0 求x²-2xy+4y²/2x²-3xy-3y²告诉下
6x²-xy-15y²=0 求2x²-3xy-3y²分之x²-2xy+4y²
谢谢高手解答x²-xy=2,-xy+y²=5求x²-2xy+ y²,x²- y²
因式分解2x(x-y)^4 - x²(x-y)² + xy(y-x)²RT
已知:x²+xy=3,xy+y²=-2 求:2x²-xy-3y²
(x+2y)²-x²-2xy
因式分解X²-3Xy+2y²+X-2