数列{an}满足a1=1,a(n+1)=2^(n+1)an/an+2^n(n∈N) (1)证明数列{2^n/an}是等差数列,
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数列{an}满足a1=1,a(n+1)=2^(n+1)an/an+2^n(n∈N) (1)证明数列{2^n/an}是等差数列,
数列{an}满足a1=1,a(n+1)=2^(n+1)an/an+2^n(n∈N) (1)证明数列{2^n/an}是等差数列,
数列{an}满足a1=1,a(n+1)=2^(n+1)an/an+2^n(n∈N) (1)证明数列{2^n/an}是等差数列,
同除以2^(n+1)
得a(n+1)/2^(n+1)=an/(an+2^n)
倒过来得2^(n+1)/a(n+1)=1+[(2^n)/an]
[2^(n+1)/a(n+1)]-[(2^n)/an]=1
得证
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