1.已知动圆x^2+y^2-2a*x-a*y+a^2=0(a0),则动圆圆心P的轨迹方程为多少?要详解.2.若直线x/a+y/b=1与圆x^2+y^2=1有公共点,则——?A.a^2+b^2=1 C.1/(a^2)+1/(b^2)=1 要详解.3.已知圆C:x^2+(y-1)^2=5,直线L:mx-y+1-m=0(1)求证
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![1.已知动圆x^2+y^2-2a*x-a*y+a^2=0(a0),则动圆圆心P的轨迹方程为多少?要详解.2.若直线x/a+y/b=1与圆x^2+y^2=1有公共点,则——?A.a^2+b^2=1 C.1/(a^2)+1/(b^2)=1 要详解.3.已知圆C:x^2+(y-1)^2=5,直线L:mx-y+1-m=0(1)求证](/uploads/image/z/2000280-48-0.jpg?t=1.%E5%B7%B2%E7%9F%A5%E5%8A%A8%E5%9C%86x%5E2%2By%5E2-2a%2Ax-a%2Ay%2Ba%5E2%3D0%28a0%29%2C%E5%88%99%E5%8A%A8%E5%9C%86%E5%9C%86%E5%BF%83P%E7%9A%84%E8%BD%A8%E8%BF%B9%E6%96%B9%E7%A8%8B%E4%B8%BA%E5%A4%9A%E5%B0%91%3F%E8%A6%81%E8%AF%A6%E8%A7%A3.2.%E8%8B%A5%E7%9B%B4%E7%BA%BFx%2Fa%2By%2Fb%3D1%E4%B8%8E%E5%9C%86x%5E2%2By%5E2%3D1%E6%9C%89%E5%85%AC%E5%85%B1%E7%82%B9%2C%E5%88%99%E2%80%94%E2%80%94%3FA.a%5E2%2Bb%5E2%3D1+C.1%2F%28a%5E2%29%2B1%2F%28b%5E2%29%3D1+%E8%A6%81%E8%AF%A6%E8%A7%A3.3.%E5%B7%B2%E7%9F%A5%E5%9C%86C%EF%BC%9Ax%5E2%2B%28y-1%29%5E2%3D5%2C%E7%9B%B4%E7%BA%BFL%EF%BC%9Amx-y%2B1-m%3D0%281%29%E6%B1%82%E8%AF%81)
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