x:y=3:2;y:z=5:4;x+y+z=66加减法过程怎么算?
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x:y=3:2;y:z=5:4;x+y+z=66加减法过程怎么算?
x:y=3:2;y:z=5:4;x+y+z=66加减法过程怎么算?
x:y=3:2;y:z=5:4;x+y+z=66加减法过程怎么算?
X:Y=3:2,x=3y/2
Y:Z=5:4,z=4y/5
所以3y/2+4y/5+y=66
解得y=20
所以x=30,z=16
所以方程组的解是
x=30
y=20
z=16
X:Y=3:2,x=3y/2
Y:Z=5:4,z=4y/5
所以3y/2+4y/5+y=66
解得y=20
所以x=30,z=16
所以方程组的解是
x=30
y=20
z=16
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
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x:y=3:2 y:z=5:4 x+y+z=66
x:y=3:2 y:z=5:4 x+y+z=66
{x:y=2:3 y:z=4:5 x+y+z=35
x:y=2:3 y:z=4:5 x+y+z=35
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