如图,角CAE=15°,AE=CE,四边形ABCD为正方形,求证:三角形BED为等边三角形.证明:∵正方形ABCD,∴AB=CD,∠BAD=∠CDA=90°,∵∠PAD=∠PDA=15°,∴PA=PD,∠PAB=∠PDC=75°,在正方形内做△DGC与△ADP全等,
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/05 14:33:57
![如图,角CAE=15°,AE=CE,四边形ABCD为正方形,求证:三角形BED为等边三角形.证明:∵正方形ABCD,∴AB=CD,∠BAD=∠CDA=90°,∵∠PAD=∠PDA=15°,∴PA=PD,∠PAB=∠PDC=75°,在正方形内做△DGC与△ADP全等,](/uploads/image/z/2002073-41-3.jpg?t=%E5%A6%82%E5%9B%BE%2C%E8%A7%92CAE%3D15%C2%B0%2CAE%3DCE%2C%E5%9B%9B%E8%BE%B9%E5%BD%A2ABCD%E4%B8%BA%E6%AD%A3%E6%96%B9%E5%BD%A2%2C%E6%B1%82%E8%AF%81%EF%BC%9A%E4%B8%89%E8%A7%92%E5%BD%A2BED%E4%B8%BA%E7%AD%89%E8%BE%B9%E4%B8%89%E8%A7%92%E5%BD%A2.%E8%AF%81%E6%98%8E%EF%BC%9A%E2%88%B5%E6%AD%A3%E6%96%B9%E5%BD%A2ABCD%EF%BC%8C%E2%88%B4AB%3DCD%EF%BC%8C%E2%88%A0BAD%3D%E2%88%A0CDA%3D90%C2%B0%EF%BC%8C%E2%88%B5%E2%88%A0PAD%3D%E2%88%A0PDA%3D15%C2%B0%EF%BC%8C%E2%88%B4PA%3DPD%EF%BC%8C%E2%88%A0PAB%3D%E2%88%A0PDC%3D75%C2%B0%EF%BC%8C%E5%9C%A8%E6%AD%A3%E6%96%B9%E5%BD%A2%E5%86%85%E5%81%9A%E2%96%B3DGC%E4%B8%8E%E2%96%B3ADP%E5%85%A8%E7%AD%89%EF%BC%8C)
xT_oV*Q%2iV NBHI{jJXMRMuLiSνvTh}e{k3dgO7TY|~$_Ɋݞys{4[<=^wMSӄH'EQ4vz2h)+87YQ5Ч}
3Лq0΄̮b)ݨyLkf]<]n4=;7ηV'*oy"Q|:ǕRJ\SU)|rw˕U~(_Ik"BW5Wܜq`.l$|!'">\$B6KivdgmFb dRjJRLgh/⨗bIYִ3(eX$ ]bGGbh̥Qe"\ZS3f9Ls>Njo5XS^XDgiㆷtn0Ho_O#GXX4b>{3>7?$ HБ(faÊAF56?X0*EÆ5IisH+aհ3|-fwÝE.il67O5*P