(1+0.23+0.34)x(0.23+0.34+0.78)-(1+0.23+0.34+0.78)x(0.23+0.34)
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(1+0.23+0.34)x(0.23+0.34+0.78)-(1+0.23+0.34+0.78)x(0.23+0.34)
(1+0.23+0.34)x(0.23+0.34+0.78)-(1+0.23+0.34+0.78)x(0.23+0.34)
(1+0.23+0.34)x(0.23+0.34+0.78)-(1+0.23+0.34+0.78)x(0.23+0.34)
设A=0.23+0.34,B=0.23+0.34+0.78
原式=(1+A)×B-(1+B)×A
=B+AB-A-AB
=B-A
=0.78
设0.23+0.34为A
原式化为(1+A)(0.78+A)-(1.78+A)A=0.78
设A=0.23+0.34,,,B=0.23+0.34+0.78
原式=(1+A)×B-(1+B)×A
=B+AB-A-AB
=B-A
=0.78
(1+0.23+0.34)x(0.23+0.34+0.65)-(1+0.23+0.34+0.65)x(0.23+0.(1+0.23+0.34)x(0.23+0.34+0.65)-(1+0.23+0.34+0.65)x(0.23+0.
(1+0.23+0.34)x(0.23+0.34+0.78)-(1+0.23+0.34+0.78)x(0.23+0.34)
简便运算 (1+0.12+0.23)x(0.12+0.23+0.34)-(1+0.12+0.23+0.34)x(0.12+0.23)
(1+0.12+0.23)X(0.12+0.23+0.34)-(1+0.12+0.23+0.34)X(0.12+0.23)=?
简便运算(1+0.12+0.23)X(0.12+0.23+0.34) - (1+0.12+0.34)X(0.12+0.23)
(1+0.12+0.23)x(0.12+0.23+0.34)-(1+0.12+0.23+0.34)x(0.12+0.23)等于几?用简便方法计算!
x-0.23x=1.54,
(1+0.23+0.34)x(0.23+0.34+0.65)-(1+0.23+0.34+0.65)x(0.23+0.34)=多少,老兄看不懂!请仔细一点
请教一道小学算术题用最简便的方法(1+0.23+0.34)X(0.23+0,34+0.65)-(1+0.23+0.34+0.65)X(0.23+0.34)=
(x-1):0.5=4.6:0.23
x-1/4.6=0.5/0.23
0.7x+1.73=1.5x-0.23
0.7x+1.37=1.5x-0.23 x=?
x/x+(1-x)/x-1/x
matlab解微分方程组出现错误程序如下:function f=shier(t,x)f(1)=x(3)*x(1)*(1-x(1)/0.23)-0.2*x(1)*x(2);f(2)=0.2*x(1)*x(2)-0.18*x(2)-0.2*x(2);f(3)=0.18*x(2)-0.1*x(3);然后这个就出现错误了:Input argument x is undefined.Error in
1 (2/3-1/2)x=1/3225%x:5=0.23x-3/5x=3/5×2/941.6x+1.5×4=1655-5/6x=1/3
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