这些一元二次方程的解答公式是什么 (就是说出它们是用提公因式法 或者 十字相乘法)(6)3x²+2x-1=0(7)10x²-x-3=0 (8)4(3x+10)²-9=0 (9)5(2x-1)=(1-2x)(x+3)(10)t(2t-10=3(2t-1) (11)y
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![这些一元二次方程的解答公式是什么 (就是说出它们是用提公因式法 或者 十字相乘法)(6)3x²+2x-1=0(7)10x²-x-3=0 (8)4(3x+10)²-9=0 (9)5(2x-1)=(1-2x)(x+3)(10)t(2t-10=3(2t-1) (11)y](/uploads/image/z/2095703-71-3.jpg?t=%E8%BF%99%E4%BA%9B%E4%B8%80%E5%85%83%E4%BA%8C%E6%AC%A1%E6%96%B9%E7%A8%8B%E7%9A%84%E8%A7%A3%E7%AD%94%E5%85%AC%E5%BC%8F%E6%98%AF%E4%BB%80%E4%B9%88+%EF%BC%88%E5%B0%B1%E6%98%AF%E8%AF%B4%E5%87%BA%E5%AE%83%E4%BB%AC%E6%98%AF%E7%94%A8%E6%8F%90%E5%85%AC%E5%9B%A0%E5%BC%8F%E6%B3%95+%E6%88%96%E8%80%85+%E5%8D%81%E5%AD%97%E7%9B%B8%E4%B9%98%E6%B3%95%EF%BC%89%EF%BC%886%EF%BC%893x%26%23178%3B%2B2x-1%3D0%EF%BC%887%EF%BC%8910x%26%23178%3B-x-3%3D0+%EF%BC%888%EF%BC%894%EF%BC%883x%2B10%29%26%23178%3B-9%3D0+%EF%BC%889%EF%BC%895%EF%BC%882x-1%29%3D%281-2x%29%28x%2B3%29%2810%29t%282t-10%3D3%282t-1%29+%EF%BC%8811%EF%BC%89y%26%231)
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