已知b-(1/2)a²=0,化简:(3ab+3b)/(a²+b)

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已知b-(1/2)a²=0,化简:(3ab+3b)/(a²+b)
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已知b-(1/2)a²=0,化简:(3ab+3b)/(a²+b)
已知b-(1/2)a²=0,化简:(3ab+3b)/(a²+b)

已知b-(1/2)a²=0,化简:(3ab+3b)/(a²+b)
∵b-(1/2)a²=0
∴a²=2b
(3ab+3b)/(a²+b)
=3b(a+1)/(2b+b)
=a+1

解:
b=1/2a^2
(3ab+3b)/(a²+b)
=(3/2a^3+3/2a^2)/(3/2a^2)
=a+1