把0.02摩尔每升CH3COOH溶液和0.01摩尔每升的NaOH溶液以等体积混合,则混合液中微粒浓度关系正确的是A.c(CH3COO-)>C(Na+)B.c(OH-)>c(H+)C.c(CH3COOH)>c(CH3COO-)D.c(CH3COOH)+c(CH3COO-)=0.01mol/L
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![把0.02摩尔每升CH3COOH溶液和0.01摩尔每升的NaOH溶液以等体积混合,则混合液中微粒浓度关系正确的是A.c(CH3COO-)>C(Na+)B.c(OH-)>c(H+)C.c(CH3COOH)>c(CH3COO-)D.c(CH3COOH)+c(CH3COO-)=0.01mol/L](/uploads/image/z/2097735-15-5.jpg?t=%E6%8A%8A0.02%E6%91%A9%E5%B0%94%E6%AF%8F%E5%8D%87CH3COOH%E6%BA%B6%E6%B6%B2%E5%92%8C0.01%E6%91%A9%E5%B0%94%E6%AF%8F%E5%8D%87%E7%9A%84NaOH%E6%BA%B6%E6%B6%B2%E4%BB%A5%E7%AD%89%E4%BD%93%E7%A7%AF%E6%B7%B7%E5%90%88%2C%E5%88%99%E6%B7%B7%E5%90%88%E6%B6%B2%E4%B8%AD%E5%BE%AE%E7%B2%92%E6%B5%93%E5%BA%A6%E5%85%B3%E7%B3%BB%E6%AD%A3%E7%A1%AE%E7%9A%84%E6%98%AFA.c%28CH3COO-%29%3EC%28Na%2B%29B.c%28OH-%29%3Ec%28H%2B%29C.c%28CH3COOH%29%3Ec%28CH3COO-%29D.c%28CH3COOH%29%2Bc%28CH3COO-%29%3D0.01mol%2FL)
把0.02摩尔每升CH3COOH溶液和0.01摩尔每升的NaOH溶液以等体积混合,则混合液中微粒浓度关系正确的是A.c(CH3COO-)>C(Na+)B.c(OH-)>c(H+)C.c(CH3COOH)>c(CH3COO-)D.c(CH3COOH)+c(CH3COO-)=0.01mol/L
把0.02摩尔每升CH3COOH溶液和0.01摩尔每升的NaOH溶液以等体积混合,则混合液中微粒浓度关系正确的是
A.c(CH3COO-)>C(Na+)
B.c(OH-)>c(H+)
C.c(CH3COOH)>c(CH3COO-)
D.c(CH3COOH)+c(CH3COO-)=0.01mol/L
把0.02摩尔每升CH3COOH溶液和0.01摩尔每升的NaOH溶液以等体积混合,则混合液中微粒浓度关系正确的是A.c(CH3COO-)>C(Na+)B.c(OH-)>c(H+)C.c(CH3COOH)>c(CH3COO-)D.c(CH3COOH)+c(CH3COO-)=0.01mol/L
0.02摩尔每升CH3COOH溶液和0.01摩尔每升的NaOH溶液以等体积混合,
不妨设各为1L,则CH3COOH过量,得到的就是0.01mol的CH3COOH与0.01mol的CH3COONa的混合溶液
这种情况下,先判断溶液显酸性,即CH3COOH的电离程度要大于CH3COONa的水解
所以,H+ > OH-
据电荷守恒,则CH3COO^- > Na+
A.c(CH3COO-)>C(Na+),对
B.c(OH-)>c(H+),错
C.c(CH3COOH)>c(CH3COO-),错,不妨认为CH3COONa不水解,而CH3COOH部分电离,所以,CH3COO^- > CH3COOH
D.c(CH3COOH)+c(CH3COO-)=0.01mol/L ,对,据物料守恒,CH3COOH与CH3COO^-共0.02mol,溶液体积为2L,所以,浓度之和为0.01mol/L
摩尔庄园
A、D正确