请解析,如图,在五边形ABCDE中,∠BAE=120°...如下如图,在五边形ABCDE中,∠BAE=120°,∠B=∠E=90°.AB=BC,AE=DE,在BC,DE上分别找一点M,N,使得△AMN的周长最小时,则∠AMN+∠ANM的度数为( )A.100° B.110° C.120° D.1
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![请解析,如图,在五边形ABCDE中,∠BAE=120°...如下如图,在五边形ABCDE中,∠BAE=120°,∠B=∠E=90°.AB=BC,AE=DE,在BC,DE上分别找一点M,N,使得△AMN的周长最小时,则∠AMN+∠ANM的度数为( )A.100° B.110° C.120° D.1](/uploads/image/z/2122366-22-6.jpg?t=%E8%AF%B7%E8%A7%A3%E6%9E%90%2C%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E4%BA%94%E8%BE%B9%E5%BD%A2ABCDE%E4%B8%AD%2C%E2%88%A0BAE%3D120%C2%B0...%E5%A6%82%E4%B8%8B%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E4%BA%94%E8%BE%B9%E5%BD%A2ABCDE%E4%B8%AD%2C%E2%88%A0BAE%3D120%C2%B0%2C%E2%88%A0B%3D%E2%88%A0E%3D90%C2%B0.AB%3DBC%2CAE%3DDE%2C%E5%9C%A8BC%2CDE%E4%B8%8A%E5%88%86%E5%88%AB%E6%89%BE%E4%B8%80%E7%82%B9M%2CN%2C%E4%BD%BF%E5%BE%97%E2%96%B3AMN%E7%9A%84%E5%91%A8%E9%95%BF%E6%9C%80%E5%B0%8F%E6%97%B6%2C%E5%88%99%E2%88%A0AMN%2B%E2%88%A0ANM%E7%9A%84%E5%BA%A6%E6%95%B0%E4%B8%BA%EF%BC%88+%EF%BC%89A.100%C2%B0+B.110%C2%B0+C.120%C2%B0+D.1)
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