数列an,bn满足a1=b1=1,an+1-an=bn+1/bn=2,则数列ban的前10项和为

数列an,bn满足a1=b1=1,an+1-an=bn+1/bn=2,则数列ban的前10项和为 数列an满足,a1=1/4,a2=3/4,an+1=2an-an-1(n≥2,n属于N*),数列bn满足b1 数列{an}{bn}满足an=5an-1 -6bn-1 bn=3an-1 -4bn-1 且a1=a,b1=b求{an}{bn}通项 设各项均为正数的数列{an}和{bn}满足:an,bn,an+1成等差数列,bn,an+1,bn+1等比数列且a1=1,b1=2,a2=3求通项an,bn 设各项均为正数的数列｛an}和｛bn}满足：an,bn,an+1成等差数列,bn,an+1,bn+1成等比数列,且a1=1,b1=2,a2=3,求通项an,bn 已知数列{an}满足an+Sn=n,数列{bn}满足b1=a1,且bn=an-a(n-1),(n≥2）,试求数列{bn}的前n项的和Tn 数列{an}的前n项和为Sn,a1=1 an+1-an*1=0,数列{bn}满足b1=2,anbn+1=2an+1bn求 s200 求bn 设数列{an}{bn}满足a1=b1=6 a2=b2=4 a3=b3=3若{an+1 - an}为等差数列.{bn+1 -bn}为等比数列.分别求{an}{bn}的通项公式. 已知数列{an},{bn}满足a1=b1=1,an-1-an=bn+1/bn=2求{Ban}和[an/bn}的前n项和 已知数列{an}满足a1=1,a2=3,an+2=3an+1-2an(n属於N+）证明数列{an+1-an}是等比数列?若数列{bn}满足(4^b1-1)(4^b2-1)……(4^bn-1)=(an+1)^bn,证明数列{bn}是等差数列？ 已知函数f(x)=x/2x+1,x>0,数列{an}满足a1=1,an+1=f(an)；数列{bn}满足b1=1/2,bn+1=1/1-2f（Sn）,其中已知函数f(x)=x/2x+1，x>0，数列{an}满足a1=1，an+1=f(an)；数列{bn}满足b1=1/2，bn+1=1/1-2f（Sn），其中Sn为数列{bn}前 数列an的前n项和为sn有数列bn它满足关系b1=an有an+sn=n bn+1=an+1-an证bn是等比数列并求其通向公式数列an的前n项和为sn 有数列bn,它满足关系b1=a1,对于n属于N+ 有an+sn=n bn+1=an+1-an 证bn是等比数列并求其 已知数列an满足a1=1,an+1=2an+1(n∈正整数) （1）求数列an的通项公式（2）若数列｛bn}满足4^(1-1)4^（b2-1)...4(bn-1)=(An+1)^bn证明｛bn}是等差数列坐等第二问!改一下！！！（2）若数列｛bn}满足4^(b1-1)4^ 设数列an为等比数列,数列bn满足bn=na1+(n-1)a2+...+2an-1+an已知b1=1,b2=4第一问为什么可以“由已知b1=a1” 设数列{an}和{bn}满足:a1=b1=6,a2=b2=4,a3=b3=3,数列{an+1-an}是等差数列···设数列{an}和{bn}满足:a1=b1=6,a2=b2=4,a3=b3=3,数列{an+1-an}是等差数列,Sn为数列{bn}的前n项和,且Sn=2n-bn+10,(1)分别求{an}{bn}的通项公式(2 已知数列{an},{bn}满足a1=2,2an=1+2an*an+1,设{bn}=an-1求数列{1n}为等差数列急！！！ 设数列an,bn分别满足a1*a2*a3...*an=1*2*3*4...*n,b1+b2+b3+...bn=an^2,n属于N+a1*a2*a3...*an=1*2*3*4...*n,b1+b2+b3+...bn=an^2,n属于N+1)求数列an和bn的通项公式 数列{an}与{bn}满足an=1/n(b1+b2+…+bn)(n∈N).求证:数列{bn}为等差数列的充要条件是数列{an}为等差数列