我自己做出来了但是答案怎么都不对..The equilibrium reaction ZnO(g)+H2(g)===Zn(g)+H2O(g)At a temperature of 1180 ℃ and at a pressure of 4.8 atm has the following gaseous composition :Zn=35% H2=25% H2O=40% (by volume) calculate the gra
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![我自己做出来了但是答案怎么都不对..The equilibrium reaction ZnO(g)+H2(g)===Zn(g)+H2O(g)At a temperature of 1180 ℃ and at a pressure of 4.8 atm has the following gaseous composition :Zn=35% H2=25% H2O=40% (by volume) calculate the gra](/uploads/image/z/2266629-69-9.jpg?t=%E6%88%91%E8%87%AA%E5%B7%B1%E5%81%9A%E5%87%BA%E6%9D%A5%E4%BA%86%E4%BD%86%E6%98%AF%E7%AD%94%E6%A1%88%E6%80%8E%E4%B9%88%E9%83%BD%E4%B8%8D%E5%AF%B9..The+equilibrium+reaction+ZnO%28g%29%2BH2%28g%29%3D%3D%3DZn%28g%29%2BH2O%28g%29At+a+temperature+of+1180+%E2%84%83+and+at+a+pressure+of+4.8+atm+has+the+following+gaseous+composition+%3AZn%3D35%25+H2%3D25%25+H2O%3D40%25+%28by+volume%29+calculate+the+gra)
我自己做出来了但是答案怎么都不对..The equilibrium reaction ZnO(g)+H2(g)===Zn(g)+H2O(g)At a temperature of 1180 ℃ and at a pressure of 4.8 atm has the following gaseous composition :Zn=35% H2=25% H2O=40% (by volume) calculate the gra
我自己做出来了但是答案怎么都不对..
The equilibrium reaction
ZnO(g)+H2(g)===Zn(g)+H2O(g)
At a temperature of 1180 ℃ and at a pressure of 4.8 atm has the following gaseous composition :Zn=35% H2=25% H2O=40% (by volume) calculate the grams of zinc oxide present at equilibrium given 122.1 g of ZnO ,2 moles of H2 at 1180℃ and 1.5 atm
我自己做出来了但是答案怎么都不对..The equilibrium reaction ZnO(g)+H2(g)===Zn(g)+H2O(g)At a temperature of 1180 ℃ and at a pressure of 4.8 atm has the following gaseous composition :Zn=35% H2=25% H2O=40% (by volume) calculate the gra
这题没毛病?锌 氢气 水 的体积分数加起来都百分之百了,氧化锌是以气相存在的吗?