mathematica 斐波那契数列的两种方法有什么区别?方法一:f[1] = 1; f[2] = 1;f[n_] := f[n - 2] + f[n - 1]f[25]方法二:f[1] = 1; f[2] = 1;f[n_] := f[n] = f[n - 2] + f[n - 1]求解这两种方法的区别,为什么第一种算个f[10
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![mathematica 斐波那契数列的两种方法有什么区别?方法一:f[1] = 1; f[2] = 1;f[n_] := f[n - 2] + f[n - 1]f[25]方法二:f[1] = 1; f[2] = 1;f[n_] := f[n] = f[n - 2] + f[n - 1]求解这两种方法的区别,为什么第一种算个f[10](/uploads/image/z/2445195-3-5.jpg?t=mathematica+%E6%96%90%E6%B3%A2%E9%82%A3%E5%A5%91%E6%95%B0%E5%88%97%E7%9A%84%E4%B8%A4%E7%A7%8D%E6%96%B9%E6%B3%95%E6%9C%89%E4%BB%80%E4%B9%88%E5%8C%BA%E5%88%AB%3F%E6%96%B9%E6%B3%95%E4%B8%80%EF%BC%9Af%5B1%5D+%3D+1%3B+f%5B2%5D+%3D+1%3Bf%5Bn_%5D+%3A%3D+f%5Bn+-+2%5D+%2B+f%5Bn+-+1%5Df%5B25%5D%E6%96%B9%E6%B3%95%E4%BA%8C%EF%BC%9Af%5B1%5D+%3D+1%3B+f%5B2%5D+%3D+1%3Bf%5Bn_%5D+%3A%3D+f%5Bn%5D+%3D+f%5Bn+-+2%5D+%2B+f%5Bn+-+1%5D%E6%B1%82%E8%A7%A3%E8%BF%99%E4%B8%A4%E7%A7%8D%E6%96%B9%E6%B3%95%E7%9A%84%E5%8C%BA%E5%88%AB%2C%E4%B8%BA%E4%BB%80%E4%B9%88%E7%AC%AC%E4%B8%80%E7%A7%8D%E7%AE%97%E4%B8%AAf%5B10)
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