:x3+y3-z3=96 xyz=4 x2+y2+z2-xy+yz+xz=12 求x+y-z
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:x3+y3-z3=96 xyz=4 x2+y2+z2-xy+yz+xz=12 求x+y-z
:x3+y3-z3=96 xyz=4 x2+y2+z2-xy+yz+xz=12 求x+y-z
:x3+y3-z3=96 xyz=4 x2+y2+z2-xy+yz+xz=12 求x+y-z
a³+b³+c³-3abc
=[( a+b)³-3a²b-3ab²]+c³-3abc
=[(a+b)³+c³]-(3a²b+3ab²+3abc)
=(a+b+c)[(a+b)²-(a+b)c+c²]-3ab(a+b+c)
=(a+b+c)(a²+b²+2ab-ac-bc+c²)-3ab(a+b+c)
=(a+b+c)(a²+b²+c²-ab-ac-bc)
令a=x,b=y,c=-z
x³+y³-z³+3xyz=(x+y-z)(x²+y²+z²-xy+ac+bc)
96+3*4=(x+y-z)*12
x+y-z=96
:x3+y3-z3=96 xyz=4 x2+y2+z2-xy+yz+xz=12 求x+y-z
x3+y3+z3-3xyz=2011 x大于等于15 y大于等于15
x3 y3 z3=x+y+z,x2+y2+z2=xyz的正实数解打错了,应该是x3+y3+z3=x+y+z
已知:x3+y3-z3=96 xyz=4 x2+y2+z2-xy+yz+xz=12 求x+y-z
已知x+y+z=3,x2+y2+z2=19,x3+y3+z3=30则xyz=?
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若x,y,z大于等于0,求证:x3+y3+z3大于等于3xyz
因式分解:x3(y-z)+y3(z-x)+z3(x-y)=
已知x+y+z=2,x2+y2+z2=12则x3+y3+z3=
已知x+y+z=2,x2+y2+z2=12则x3+y3+z3=
X+Y+Z=0 X3+Y3+Z3=?3就是3次幂