90/(x-90)=(2x-50)/(x+50)

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90/(x-90)=(2x-50)/(x+50)
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90/(x-90)=(2x-50)/(x+50)
90/(x-90)=(2x-50)/(x+50)

90/(x-90)=(2x-50)/(x+50)
90/(x-90)=(2x-50)/(x+50)

(2x-50)(x-90)=90(x+50)
2x^2-230x+4500=90x+4500
2x^2-230x-90x+4500-4500=0
2x^2-320x=0
x^2-160x=0
x(x-160)=0
x1=0 x2=160

90(x+50)=(x-90)(2x-50)
90x+4500=2(x)^2-180x-50x+4500
90x=2(x)^2-230x
45x=x^2-230x
45x=x(x-115)
45=x-115
x=160/0
望被采纳o!

先把这个方程化成一般方程然后求解