已知如图,在等腰梯形ABCD中,AD‖BC,AB=CD,AD=3,BC=9,tan∠ABC=4/3,直线MN是梯形的对称轴,点P是线段MN上一个动点(不与M、N重合),射线BP交线段CD与点E,过点C作CF‖AB交射线BP于点F(1)求证:PC²=PE·P
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![已知如图,在等腰梯形ABCD中,AD‖BC,AB=CD,AD=3,BC=9,tan∠ABC=4/3,直线MN是梯形的对称轴,点P是线段MN上一个动点(不与M、N重合),射线BP交线段CD与点E,过点C作CF‖AB交射线BP于点F(1)求证:PC²=PE·P](/uploads/image/z/2481970-58-0.jpg?t=%E5%B7%B2%E7%9F%A5%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E7%AD%89%E8%85%B0%E6%A2%AF%E5%BD%A2ABCD%E4%B8%AD%2CAD%E2%80%96BC%2CAB%3DCD%2CAD%3D3%2CBC%3D9%2Ctan%E2%88%A0ABC%3D4%2F3%2C%E7%9B%B4%E7%BA%BFMN%E6%98%AF%E6%A2%AF%E5%BD%A2%E7%9A%84%E5%AF%B9%E7%A7%B0%E8%BD%B4%2C%E7%82%B9P%E6%98%AF%E7%BA%BF%E6%AE%B5MN%E4%B8%8A%E4%B8%80%E4%B8%AA%E5%8A%A8%E7%82%B9%EF%BC%88%E4%B8%8D%E4%B8%8EM%E3%80%81N%E9%87%8D%E5%90%88%EF%BC%89%2C%E5%B0%84%E7%BA%BFBP%E4%BA%A4%E7%BA%BF%E6%AE%B5CD%E4%B8%8E%E7%82%B9E%2C%E8%BF%87%E7%82%B9C%E4%BD%9CCF%E2%80%96AB%E4%BA%A4%E5%B0%84%E7%BA%BFBP%E4%BA%8E%E7%82%B9F%EF%BC%881%EF%BC%89%E6%B1%82%E8%AF%81%EF%BC%9APC%26sup2%3B%3DPE%C2%B7P)
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