已知x.y满足(x-y+2>=0.x+y-4>=0.2x-y-5<=0),求Z=[x+2y-4]的最大值……补充:[]为绝对值符号…
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/01 21:30:48
![已知x.y满足(x-y+2>=0.x+y-4>=0.2x-y-5<=0),求Z=[x+2y-4]的最大值……补充:[]为绝对值符号…](/uploads/image/z/2486412-36-2.jpg?t=%E5%B7%B2%E7%9F%A5x.y%E6%BB%A1%E8%B6%B3%EF%BC%88x-y%2B2%EF%BC%9E%EF%BC%9D0.x%2By-4%EF%BC%9E%EF%BC%9D0.2x-y-5%EF%BC%9C%EF%BC%9D0%EF%BC%89%2C%E6%B1%82Z%3D%5Bx%2B2y-4%5D%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC%E2%80%A6%E2%80%A6%E8%A1%A5%E5%85%85%EF%BC%9A%5B%5D%E4%B8%BA%E7%BB%9D%E5%AF%B9%E5%80%BC%E7%AC%A6%E5%8F%B7%E2%80%A6)
xPK
@VGEڃ(. Rt3`ҥPnFwsSD
2|ӈfmϟd
l"8?AH+IdZN
已知x.y满足(x-y+2>=0.x+y-4>=0.2x-y-5<=0),求Z=[x+2y-4]的最大值……补充:[]为绝对值符号…
已知x.y满足(x-y+2>=0.x+y-4>=0.2x-y-5<=0),求Z=[x+2y-4]的最大值……补充:[]为绝对值符号…
已知x.y满足(x-y+2>=0.x+y-4>=0.2x-y-5<=0),求Z=[x+2y-4]的最大值……补充:[]为绝对值符号…
根据不等式组,可以求得 7≥x≥1,9≥y≥3
所以25≥x+2y≥7
所以,Z的最大值=21
已知x,y满足y
已知实数x,y满足x-y
已知实数X,Y满足{|x+y|
已知实数x.y满足(x+2)^2+y^2(
已知圆x,y满足x^2+y^2
已知x,y满足x+y-2>=0,2x-y+2>=0,x
已知x,y满足约束条件:x-y+1>=0,x+y-2>=0,x
已知x.y满足X2-y2=2xy.则x-y/x+y=?x.
已知实数x,y满足:y
已知实数x,y满足约束条件x+y>3,y
已知x.y满足(x-y+2>=0.x+y-4>=0.2x-y-5<=0),求Z=[x+2y-4]的最大值……补充:[]为绝对值符号…
已知实数x,y满足方程x^2+y^2-4x-2y+1=0.求x^2+y^2+x+y的最大值和最小值.
已知x,y满足{x>=1,x+y
已知x,y满足{x>=1,x+y
已知x和y满足x+3y+|3x-y|=19,2x+y=6,求x,y的值
已知实数x,y满足x²+√2 y=√3,y²+√2 x=√3,则x/y+y/x=?
已知实数X,Y满足2
已知实数xy满足x+2y