x+{40-[42-(18-x)]}怎么算

来源：学生作业帮助网 编辑：作业帮 时间：2024/11/23 18:55:50
x+{40-[42-(18-x)]}怎么算
x)Ю61Ѝ610ЭЌ}dgum6BUIH"5q!K1

x+{40-[42-(18-x)]}怎么算
x+{40-[42-(18-x)]}怎么算

x+{40-[42-(18-x)]}怎么算
=x+40-[42-(18-x)]
=x+40-42+(18-x)
=x-2+18-x
=16

x+{40-[42-(18-x)]}
=x+40-42+18-x
=16

计算 顺序是小括号-中括号-大括号
x+{40-[42-(18-x)]}
=x+{40-[42-18+x)]}
=x+{40-[24+x)]}
=x+{40-24-x)]}
=x+{16-x)]}
=x+16-x
=16

x+{40-[42-(18-x)]}
=x+40-42+18-x
=16

x+{40-[42-(18-x)]}怎么算 50x=40x(18-x)怎么解 x/40%x=18怎么解x除以40%x=18怎么解? x^2=(x+30)X(x-18)怎么解 X-18=40％X+18怎么解? 1/3x+18=40%x怎么解? 2*x*x*x-6x*x+18x怎么因式分解? 3.8x-x=42怎么解? x-0.8x=42怎么解 3.8x-x=42怎么解? 3x=x+18怎么解? 3.5x+x=18怎么解 X+18X=20 怎么解? 18+X=1.1X怎么解 361-x/x=18怎么解 x(18-x)=81怎么算, 2x x=18怎么算 X(18-X)=81怎么解