在三角形ABC中,已知sin(B+2/C)=4/5,求COS(A-B)的值是C/2,

来源:学生作业帮助网 编辑:作业帮 时间:2024/07/12 11:24:59
在三角形ABC中,已知sin(B+2/C)=4/5,求COS(A-B)的值是C/2,
x){:gœ/Ozwkun|< 'm#}gM[}Sg5u4jyڰٌF:6IE 3IΆJ r5\[_eFN@)s~ F)A8# ]C~qAb'6`JOzH>r' Sx/҉

在三角形ABC中,已知sin(B+2/C)=4/5,求COS(A-B)的值是C/2,
在三角形ABC中,已知sin(B+2/C)=4/5,求COS(A-B)的值
是C/2,

在三角形ABC中,已知sin(B+2/C)=4/5,求COS(A-B)的值是C/2,
Sin(B+C/2)
=Sin(B+(90度-A/2-B/2))
=Cos(B/2-A/2)
=Cos(A/2-B/2)
Cos(A-B)
=2Cos^2(A/2-B/2)-1
=3/5

"2/C"会不会打错了?????????
Sin(B+C/2)
=Sin(B+(90度-A/2-B/2))
=Cos(B/2-A/2)
=Cos(A/2-B/2)
Cos(A-B)
=2Cos^2(A/2-B/2)-1
=3/5