当x等于x的相反数时,分式(x^2-1)[(x+1)/(x-1)+(x-1)/(x+1)-(x^2-1)/1]=?

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当x等于x的相反数时,分式(x^2-1)[(x+1)/(x-1)+(x-1)/(x+1)-(x^2-1)/1]=?
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当x等于x的相反数时,分式(x^2-1)[(x+1)/(x-1)+(x-1)/(x+1)-(x^2-1)/1]=?
当x等于x的相反数时,分式(x^2-1)[(x+1)/(x-1)+(x-1)/(x+1)-(x^2-1)/1]=?

当x等于x的相反数时,分式(x^2-1)[(x+1)/(x-1)+(x-1)/(x+1)-(x^2-1)/1]=?
相反数等于本身的只有0,
(x^2-1)[(x+1)/(x-1)+(x-1)/(x+1)-(x^2-1)/1]
=-1×(-1-1+1)
=1

当x等于x的相反数时,x等于且只等于0,代入得
-1*[-1-1+1]=1