若x+y=8 y+z=12 x+z=10 则x+y+z =多少

x+y=8 y+z=12 x+z=10 x+y+z= x+y=8 y+z=12 x+z=10 x+y+z= 若X/10=Y/8=Z/9则X+Y+Z/Y+Z=? 若x+y=8 y+z=12 x+z=10 则x+y+z =多少 (x+y-z)(x-y+z)= X/10=Y/8=Z/9,则X+Y+Z/2Y-3Z 若z分之x+y+z=y分之x-y+z=x分之-x+y+z,求xyz分之(x+y)(y+z)(z+x) 已知x+y=8,y+z=12,x+z=10,则x+y+z=? X=3z X+y+z=12 X+2y-2z=10 X+Y+Z=? x/y=(x+z)/(y+z)y/z=(x+y)/(x+z) 已知x+y=8,x+z=12,x+z=10,则x+Y+z等于几? (x+y+z)÷10=x+1.1 y+x=z-80+y-1 z-y=8x+y+8 x+z÷y=? 已知 x/(y+z)+y/(z+x)+z/(x+y)=1求 (x*x)/(y+z)+(y*y)/(x+z)+(z*z)/(x+y)=? (4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=? 若x除以10=y除以8=z除以9,则x+y+z除以y+z (y+z)/x=(z+x)/y=(x+y)/z求x+y-z/x+y+z的值 解方程 x(x+y+z)=6 y(x+y+z)=12 z(x+y+z)=18