作业帮3x+2y-z=1,2x-y+2z=5,5x-2y+3z=13
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3x+2y-z=1,2x-y+2z=5,5x-2y+3z=13
3x+2y-z=1,2x-y+2z=5,5x-2y+3z=13
3x+2y-z=1,2x-y+2z=5,5x-2y+3z=13
消去一个未知数 x=2 y=-3 z=-1
第一式×2 第二式=8x 3y=7
第一式×3 第三式=14x 6y=16，即7x 3y=8
上述两式相减得x=-1,带入原式。2y-z=4,-y 2z=7
分别用a,b表示上两式，则2a b=3y=15
所以y=5,z=6
x/2=y/3=z/5 x+3y-z/x-3y+z
{x+y+z=1;x+3y+7z=-1;z+5y+8z=-2
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值
已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值
已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX..
x+y+z=6 x+2y+3z=14 y+1=z
方程组 (1) x+2y-3z=12 x-3y+2z= - 13 x-y-z=0 (2) x+ y=z 5x-y+z=18 2x+5y+3z= -1
x+Y+Z=1 X+3Y+7Z=-1 X+5Y+8Z=2x+Y+Z=1X+3Y+7Z=-1X+5Y+8Z=2
若|x+3|+|y-2|+|2×z+1|=0求(x×z-y×z)(y-x+z)的值
x+y+z=2 x-3y+2z=1 2x+2y+z+5 要具体步骤..
3x-y+2z=-1 4x+y+z=5 x-2y-z=-2
{x+y+z=1 x-2y+3z=5 2x-3y-3z=-8
2x-y+3z=3 {3X+Y-2Z=-1 X+Y+Z=5
x-y+z=-1 5x+2y-z=6 4x-3y+2z=-5
x+y+z=-5,3x+y+z=1,4x+3y+2z=-2快
3x+2y+z=14 ,x+y+z=10,z+2x+3y=1 5