已知,在三角形ABC中,角A=60度,AB=AC,BE垂直于AC于E,CF垂直于AB于F,点D为BC的中点,BE、CF交与点M,那么三角形DEF是等边三角形,请说明理由
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![已知,在三角形ABC中,角A=60度,AB=AC,BE垂直于AC于E,CF垂直于AB于F,点D为BC的中点,BE、CF交与点M,那么三角形DEF是等边三角形,请说明理由](/uploads/image/z/2558996-44-6.jpg?t=%E5%B7%B2%E7%9F%A5%2C%E5%9C%A8%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2C%E8%A7%92A%3D60%E5%BA%A6%2CAB%3DAC%2CBE%E5%9E%82%E7%9B%B4%E4%BA%8EAC%E4%BA%8EE%2CCF%E5%9E%82%E7%9B%B4%E4%BA%8EAB%E4%BA%8EF%2C%E7%82%B9D%E4%B8%BABC%E7%9A%84%E4%B8%AD%E7%82%B9%2CBE%E3%80%81CF%E4%BA%A4%E4%B8%8E%E7%82%B9M%2C%E9%82%A3%E4%B9%88%E4%B8%89%E8%A7%92%E5%BD%A2DEF%E6%98%AF%E7%AD%89%E8%BE%B9%E4%B8%89%E8%A7%92%E5%BD%A2%2C%E8%AF%B7%E8%AF%B4%E6%98%8E%E7%90%86%E7%94%B1)
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