作业帮[(1-2i)^2/(3-4i)]-[(2+i)^2/(4-3i)]=?
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/20 23:40:20
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[(1-2i)^2/(3-4i)]-[(2+i)^2/(4-3i)]=?
[(1-2i)^2/(3-4i)]-[(2+i)^2/(4-3i)]=?
[(1-2i)^2/(3-4i)]-[(2+i)^2/(4-3i)]=?
[(1-2i)^2/(3-4i)]-[(2+i)^2/(4-3i)]
=[1-4-4i)/(3-4i)]-[(4-1+4i)/(4-3i)]
=-(3+4i)/(3-4i)-(3+4i)/(4-3i)
=-(3+4i)^2/[(3-4i)(3+4i)]-(3+4i)(4+3i)/[(4-3i)(4+3i)]
=-(9-16+24i)/(9+16)-(12+9i+16i-12)/(16+9)
=(7-24i)/25-(25i)/25
=7/25-24/25i-i
=7/25-49/25i
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