高等数学中,投影柱面方程是怎么回事?已知曲线方程L:x^2/16+y^/4-z^2/5=1,x-2z+3=0,求它在xoy上的投影柱面方程.请问为什么是:先由x-2z+3=0求出z=(x+3)/2,然后将它带入x^2/16+y^/4-z^2/5=1,就得到它在xoy上
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/03 14:03:29
![高等数学中,投影柱面方程是怎么回事?已知曲线方程L:x^2/16+y^/4-z^2/5=1,x-2z+3=0,求它在xoy上的投影柱面方程.请问为什么是:先由x-2z+3=0求出z=(x+3)/2,然后将它带入x^2/16+y^/4-z^2/5=1,就得到它在xoy上](/uploads/image/z/2567508-60-8.jpg?t=%E9%AB%98%E7%AD%89%E6%95%B0%E5%AD%A6%E4%B8%AD%2C%E6%8A%95%E5%BD%B1%E6%9F%B1%E9%9D%A2%E6%96%B9%E7%A8%8B%E6%98%AF%E6%80%8E%E4%B9%88%E5%9B%9E%E4%BA%8B%3F%E5%B7%B2%E7%9F%A5%E6%9B%B2%E7%BA%BF%E6%96%B9%E7%A8%8BL%EF%BC%9Ax%5E2%2F16%2By%5E%2F4-z%5E2%2F5%3D1%2Cx-2z%2B3%3D0%2C%E6%B1%82%E5%AE%83%E5%9C%A8xoy%E4%B8%8A%E7%9A%84%E6%8A%95%E5%BD%B1%E6%9F%B1%E9%9D%A2%E6%96%B9%E7%A8%8B.%E8%AF%B7%E9%97%AE%E4%B8%BA%E4%BB%80%E4%B9%88%E6%98%AF%EF%BC%9A%E5%85%88%E7%94%B1x-2z%2B3%3D0%E6%B1%82%E5%87%BAz%3D%28x%2B3%29%2F2%2C%E7%84%B6%E5%90%8E%E5%B0%86%E5%AE%83%E5%B8%A6%E5%85%A5x%5E2%2F16%2By%5E%2F4-z%5E2%2F5%3D1%2C%E5%B0%B1%E5%BE%97%E5%88%B0%E5%AE%83%E5%9C%A8xoy%E4%B8%8A)
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