用因式分解法解下列方程:1:y(y+5)=-25/4;2:3(x-3)=(x-3)^2;3:(2x+3)^2=24x4:1.2y-0.04=9y^2
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/30 18:07:23
![用因式分解法解下列方程:1:y(y+5)=-25/4;2:3(x-3)=(x-3)^2;3:(2x+3)^2=24x4:1.2y-0.04=9y^2](/uploads/image/z/2567784-48-4.jpg?t=%E7%94%A8%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3%E6%B3%95%E8%A7%A3%E4%B8%8B%E5%88%97%E6%96%B9%E7%A8%8B%EF%BC%9A1%EF%BC%9Ay%28y%2B5%29%3D-25%2F4%3B2%3A3%28x-3%29%3D%28x-3%29%5E2%3B3%3A%282x%2B3%29%5E2%3D24x4%3A1.2y-0.04%3D9y%5E2)
用因式分解法解下列方程:1:y(y+5)=-25/4;2:3(x-3)=(x-3)^2;3:(2x+3)^2=24x4:1.2y-0.04=9y^2
用因式分解法解下列方程:1:y(y+5)=-25/4;
2:3(x-3)=(x-3)^2;
3:(2x+3)^2=24x
4:1.2y-0.04=9y^2
用因式分解法解下列方程:1:y(y+5)=-25/4;2:3(x-3)=(x-3)^2;3:(2x+3)^2=24x4:1.2y-0.04=9y^2
1:y(y+5)=-25/4
y²+5y+25/4=0
(y+5/2)²=0
y=-5/2
2:3(x-3)=(x-3)^2;
(x-3)(3-x+3)=0
(x-3)(6-x)=0
x=3 x=6
3:(2x+3)^2=24x
4x²+12x+9-24x=0
4x²-12x+9=0
(2x-3)²=0
x=3/2
4:1.2y-0.04=9y^2
9y²-1.2y+0.04=0
(3y-0.2)²=0
y=0.2/3=1/15
1 y^2+5y+25/4=0
(y+5/2)^2=0
y+5/2=0
y=-5/2
2:3(x-3)=(x-3)^2;
3x-9=x^2-6x+9
3:(2x+3)^2=24x
4x²+12x+9-24x=0
4x²-12x+9=0
(2x-3)²=0
x=3/2
4:1.2y-0.04=9y^2
9y²-1.2y+0.04=0
(3y-0.2)²=0
y=0.2/3=1/15
1:y(y+5)=-25/4
y²+5y+25/4=0
(y+5/2)²=0
y=-5/2
2:3(x-3)=(x-3)^2;
(x-3)(3-x+3)=0
(x-3)(6-x)=0
x=3 x=6
3:(2x+3)^2=24x
4x²+12x+9-24x=0
4x²-12x+9=0
(2x-3)²=0
x=3/2
4:1.2y-0.04=9y^2
9y²-1.2y+0.04=0
(3y-0.2)²=0
y=0.2/3=1/15