如图17,C在直线BE上,∠ABC与∠ACE的角平分线交于点A1(1)若∠A=60°,求∠A1的度数;(2)若∠A=m,求∠A1的度数;(3)在(2)的条件下,若再作∠A1BE,∠A1CE的平分线,交于点A2;再作∠A2BE,∠A2CE
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![如图17,C在直线BE上,∠ABC与∠ACE的角平分线交于点A1(1)若∠A=60°,求∠A1的度数;(2)若∠A=m,求∠A1的度数;(3)在(2)的条件下,若再作∠A1BE,∠A1CE的平分线,交于点A2;再作∠A2BE,∠A2CE](/uploads/image/z/2574274-58-4.jpg?t=%E5%A6%82%E5%9B%BE17%2CC%E5%9C%A8%E7%9B%B4%E7%BA%BFBE%E4%B8%8A%2C%E2%88%A0ABC%E4%B8%8E%E2%88%A0ACE%E7%9A%84%E8%A7%92%E5%B9%B3%E5%88%86%E7%BA%BF%E4%BA%A4%E4%BA%8E%E7%82%B9A1%EF%BC%881%EF%BC%89%E8%8B%A5%E2%88%A0A%EF%BC%9D60%C2%B0%2C%E6%B1%82%E2%88%A0A1%E7%9A%84%E5%BA%A6%E6%95%B0%EF%BC%9B%EF%BC%882%EF%BC%89%E8%8B%A5%E2%88%A0A%EF%BC%9Dm%2C%E6%B1%82%E2%88%A0A1%E7%9A%84%E5%BA%A6%E6%95%B0%EF%BC%9B%EF%BC%883%EF%BC%89%E5%9C%A8%EF%BC%882%EF%BC%89%E7%9A%84%E6%9D%A1%E4%BB%B6%E4%B8%8B%2C%E8%8B%A5%E5%86%8D%E4%BD%9C%E2%88%A0A1BE%2C%E2%88%A0A1CE%E7%9A%84%E5%B9%B3%E5%88%86%E7%BA%BF%2C%E4%BA%A4%E4%BA%8E%E7%82%B9A2%EF%BC%9B%E5%86%8D%E4%BD%9C%E2%88%A0A2BE%2C%E2%88%A0A2CE)
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