经过椭圆x^2/2+y^2=1的左焦点F1作倾斜角为60度的直线l,直线l与椭圆相交于A,B两点,求AB的长这是一个人的解答:c^2=2-1=1,c=1,即F1坐标为(-1,0),直线l的斜率为:tg60=√3则直线l方程为:y=√3(x+1),
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/10 23:11:27
![经过椭圆x^2/2+y^2=1的左焦点F1作倾斜角为60度的直线l,直线l与椭圆相交于A,B两点,求AB的长这是一个人的解答:c^2=2-1=1,c=1,即F1坐标为(-1,0),直线l的斜率为:tg60=√3则直线l方程为:y=√3(x+1),](/uploads/image/z/2587056-24-6.jpg?t=%E7%BB%8F%E8%BF%87%E6%A4%AD%E5%9C%86x%5E2%2F2%2By%5E2%3D1%E7%9A%84%E5%B7%A6%E7%84%A6%E7%82%B9F1%E4%BD%9C%E5%80%BE%E6%96%9C%E8%A7%92%E4%B8%BA60%E5%BA%A6%E7%9A%84%E7%9B%B4%E7%BA%BFl%2C%E7%9B%B4%E7%BA%BFl%E4%B8%8E%E6%A4%AD%E5%9C%86%E7%9B%B8%E4%BA%A4%E4%BA%8EA%2CB%E4%B8%A4%E7%82%B9%2C%E6%B1%82AB%E7%9A%84%E9%95%BF%E8%BF%99%E6%98%AF%E4%B8%80%E4%B8%AA%E4%BA%BA%E7%9A%84%E8%A7%A3%E7%AD%94%EF%BC%9Ac%5E2%3D2-1%3D1%2Cc%3D1%2C%E5%8D%B3F1%E5%9D%90%E6%A0%87%E4%B8%BA%EF%BC%88-1%2C0%EF%BC%89%2C%E7%9B%B4%E7%BA%BFl%E7%9A%84%E6%96%9C%E7%8E%87%E4%B8%BA%EF%BC%9Atg60%3D%E2%88%9A3%E5%88%99%E7%9B%B4%E7%BA%BFl%E6%96%B9%E7%A8%8B%E4%B8%BA%EF%BC%9Ay%3D%E2%88%9A3%EF%BC%88x%2B1%EF%BC%89%2C)
xS]OP+HBG9-=iI&^ziĬ]MM6cAd CƈFf@Ȉtbzzn|6=o}ߧVIo朷CJ/1ġ@ngaVL}>Jk;" N1uӵ:tvm)DCJK9Ym=מvϮ㰗GrzTYk*&QHsQ>Y?$B-f"P