sin(a+b)=-3/5,sin(b-派/4)=12/13,ab属于(3派/4,派)求cos(a+派/4)
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sin(a+b)=-3/5,sin(b-派/4)=12/13,ab属于(3派/4,派)求cos(a+派/4)
sin(a+b)=-3/5,sin(b-派/4)=12/13,ab属于(3派/4,派)
求cos(a+派/4)
sin(a+b)=-3/5,sin(b-派/4)=12/13,ab属于(3派/4,派)求cos(a+派/4)
cos(a+pi/4) = cos(a+b-b+pi/4) = cos(a+b)cos(b-pi/4)+sin(a+b)sin(b-pi/4) = -4/5*5/13-3/5*12/13 =-56/65
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3 在三角形ABC中,已知(a2+b2)sin(A-B)=(a2-b2)sin(A+B) 求证:ABC是等腰或直角三角形(a^2+b^2)sin(A-B)=(a^2-b^2)sin(A+B),(sin^A+sin^B)sin(A-B)=(sin^A-sin^B)sin(A+B) sin^A*(sin(A+B)-sin(A-B))=sin^B*(sin(A-B)+sin(A+B)) sin^A*2c
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