作业帮(1+2sinxcosx+cos^2x-sin^2x)+1这个是怎么到这步的[(cosx+sinx)(cosx+sinx+cosx-sinx]+1?用了哪个公式?
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/17 10:43:03
![(1+2sinxcosx+cos^2x-sin^2x)+1这个是怎么到这步的[(cosx+sinx)(cosx+sinx+cosx-sinx]+1?用了哪个公式?](/uploads/image/z/2625237-45-7.jpg?t=%281%2B2sinxcosx%2Bcos%5E2x-sin%5E2x%29%2B1%E8%BF%99%E4%B8%AA%E6%98%AF%E6%80%8E%E4%B9%88%E5%88%B0%E8%BF%99%E6%AD%A5%E7%9A%84%5B%28cosx%2Bsinx%29%28cosx%2Bsinx%2Bcosx-sinx%5D%2B1%3F%E7%94%A8%E4%BA%86%E5%93%AA%E4%B8%AA%E5%85%AC%E5%BC%8F%3F)
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(1+2sinxcosx+cos^2x-sin^2x)+1这个是怎么到这步的[(cosx+sinx)(cosx+sinx+cosx-sinx]+1?用了哪个公式?
(1+2sinxcosx+cos^2x-sin^2x)+1这个是怎么到这步的[(cosx+sinx)(cosx+sinx+cosx-sinx]+1?用了哪个公式?
(1+2sinxcosx+cos^2x-sin^2x)+1这个是怎么到这步的[(cosx+sinx)(cosx+sinx+cosx-sinx]+1?用了哪个公式?
解由(1+2sinxcosx+cos^2x-sin^2x)+1
=(cos^2x+sin^2x+2sinxcosx+cos^2x-sin^2x)+1
=(cos^2x+2sinxcosx+sin^2x+cos^2x-sin^2x)+1
=[(cosx+sinx)²+cos^2x-sin^2x]+1
=[(cosx+sinx)²+（cosx-sinx）（cosx+sinx）]+1
=[(cosx+sinx)（cosx+sinx+cosx-sinx）]+1
化简2*(sinxcosx-cos平方x)+1
sin^2xtanx+(cos^2x/tanx)+2sinxcosx-1+cos/sinxcosx
求证 1+2sinxcosx/sin^2x-cos^2x=sin^2x-cos^2x/1-2sinxcosx
证明1-2sinxcosx/cos^2x-sin^2x=cos^2x-sin^2/1+2sinxcosx
2sin^2x-sinxcosx-cos^2=1
化简y=2sinxcosx+2cos^2x-1
化简1+2sinxcosx+2cos²x
求cos^2x-sinxcosx-1/2单调增区间
cos^2+2sinxcosx+sin^2x
化简 根号3sinXcosX+cos*2X
y=sinxcosx+cos(2x)化简
化简:(cos*2x-0.5)/(sinxcosx)
sin^2xtanx+cos^2x/tanx+2sinxcosx-(1+cosx/sinxcosx)化简
已知tanx=2,则(1)1/4sin方x-3sinxcosx/cos方x+2sinxcosx
tanx=2,则1/4sin²x-3sinxcosx/cos²x+2sinxcosx=多少
y=(cos^2x)/(sinxcosx-sin^2x),(0
sin²X-sinxcosx+2cos²x=化简
化简f(x)=cos^2(x+π/12)+sinxcosx