作业帮求出二维数组a[ ][5]={34,3,25,75,48.45,234,32,421,1.33,23,32,43,53.76,7,78,89,56.75,65,32,53,17}每一行中的最小值和最大值并存入一个数组b中,b数组中每行有两个元素,第一个元素是最小值,第二个元素是最大值
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![求出二维数组a[ ][5]={34,3,25,75,48.45,234,32,421,1.33,23,32,43,53.76,7,78,89,56.75,65,32,53,17}每一行中的最小值和最大值并存入一个数组b中,b数组中每行有两个元素,第一个元素是最小值,第二个元素是最大值](/uploads/image/z/263118-30-8.jpg?t=%E6%B1%82%E5%87%BA%E4%BA%8C%E7%BB%B4%E6%95%B0%E7%BB%84a%5B+%5D%5B5%5D%3D%7B34%2C3%2C25%2C75%2C48.45%2C234%2C32%2C421%2C1.33%2C23%2C32%2C43%2C53.76%2C7%2C78%2C89%2C56.75%2C65%2C32%2C53%2C17%7D%E6%AF%8F%E4%B8%80%E8%A1%8C%E4%B8%AD%E7%9A%84%E6%9C%80%E5%B0%8F%E5%80%BC%E5%92%8C%E6%9C%80%E5%A4%A7%E5%80%BC%E5%B9%B6%E5%AD%98%E5%85%A5%E4%B8%80%E4%B8%AA%E6%95%B0%E7%BB%84b%E4%B8%AD%2Cb%E6%95%B0%E7%BB%84%E4%B8%AD%E6%AF%8F%E8%A1%8C%E6%9C%89%E4%B8%A4%E4%B8%AA%E5%85%83%E7%B4%A0%2C%E7%AC%AC%E4%B8%80%E4%B8%AA%E5%85%83%E7%B4%A0%E6%98%AF%E6%9C%80%E5%B0%8F%E5%80%BC%2C%E7%AC%AC%E4%BA%8C%E4%B8%AA%E5%85%83%E7%B4%A0%E6%98%AF%E6%9C%80%E5%A4%A7%E5%80%BC)
求出二维数组a[ ][5]={34,3,25,75,48.45,234,32,421,1.33,23,32,43,53.76,7,78,89,56.75,65,32,53,17}每一行中的最小值和最大值并存入一个数组b中,b数组中每行有两个元素,第一个元素是最小值,第二个元素是最大值
求出二维数组a[ ][5]={34,3,25,75,48.45,234,32,421,1.33,23,32,43,53.76,7,78,89,56.75,65,32,53,17
}每一行中的最小值和最大值并存入一个数组b中,b数组中每行有两个元素,第一个元素是最小值,第二个元素是最大值.
求出二维数组a[ ][5]={34,3,25,75,48.45,234,32,421,1.33,23,32,43,53.76,7,78,89,56.75,65,32,53,17}每一行中的最小值和最大值并存入一个数组b中,b数组中每行有两个元素,第一个元素是最小值,第二个元素是最大值
#include
void get_max_min( float a[5] , float b[2] )
{
int i=0;
b[0]=b[1]=a[0];
for( i=1; i<5 ; i++ )
{
printf("%.2lf " , a[i-1] );
if ( b[1]
if ( b[0]>a[i] ) b[0]=a[i] ;
}
printf("%.2lf\n" , a[i-1] );
printf("min=%.2lf max=%.2lf\n" , b[0] , b[1] );
}
int main()
{
float a[][5]={34,3,25,75,48.45,234,32,421,1.33,23,32,43,53.76,7,78,89,56.75,65,32,53,17};
float b[10][2]={{0,0}};
int i=0;
for( i=0;i
return 0;
}
java还是C