计算:log2(18)-2log2(6)+2^【3-log2(3)】
来源:学生作业帮助网 编辑:作业帮 时间:2024/10/01 20:58:12
x){nunahkba~OQ ƺ`Ic
mIפ_`gC]+HiAա(IIdA}#$!]C/.H̳ t
计算:log2(18)-2log2(6)+2^【3-log2(3)】
计算:log2(18)-2log2(6)+2^【3-log2(3)】
计算:log2(18)-2log2(6)+2^【3-log2(3)】
log2(18)-2log2(6)+2^【3-log2(3)】
=log2(18)-log2(36)+2^3/2^log2(3)
=log2(18/36)+8/3
=log2(1/2)+8/3
=-1+8/3
=5/3
计算:log2(18)-2log2(6)+2^【3-log2(3)】
计算:(1)log2 (4^3*8^5);(2)log2 3+log2 6-log2 9
计算:log2(log2 32-log2 3/4+log2 6)
log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2[log2(32)-log2(3÷4)+log2log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2【log2(32)-log2(3÷4)+log2(6)】=?lgx+lg(x+15)=2 ..X
计算 (Log6 3)^2+【(log6 18)/(log2 6)]
计算[log6(3)]^2+log6(18)/log2(6)
计算(log3 2)(log2 6-1)
log2^(4^7*2^5)+log2^6-log2^3
log2 6-log2 3
log2^6-log2^3
计算(1)log327+ lg 1002+ log21 (2)lg 5+lg 2+ log2 18-log2 9 (3)ln e 3 +2 log2 6 (4) log8 9×log27 32
计算2^4+ log2^3
log2 根号2怎么计算?
log2 14-2log2 7/3+log2 7-log2 18是多少2是小2
计算(log3(2))*(log2(6-1))=?__________尤其是(log2(6-1))=?
计算 log2(1+√2+√3)+log2(1+√2+√3)
怎样计算(log2)^2+(log5)^2+(2*log2)*log5
(log2) ^2 - log5 *log20课本上 等于 (log2)^2 +(1+log2)(1-log2) = 1;(log2)^2 +(1+log2)(1-log2) 是怎么来的?