设f(x)=sin兀x(x=0),g(x)=cos兀x(x=1/2)求g(1/4)+f(1/3)+g(5/6)+f(3/4)的值
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设f(x)=sin兀x(x=0),g(x)=cos兀x(x=1/2)求g(1/4)+f(1/3)+g(5/6)+f(3/4)的值
设f(x)=sin兀x(x=0),g(x)=cos兀x(x=1/2)
求g(1/4)+f(1/3)+g(5/6)+f(3/4)的值
设f(x)=sin兀x(x=0),g(x)=cos兀x(x=1/2)求g(1/4)+f(1/3)+g(5/6)+f(3/4)的值
g(1/4)+f(1/3)+g(5/6)+f(3/4)
=cos(兀/4)+f(-2/3)+1+g(-1/6)+1+f(-1/4)+1
=√2/2-√3/2+1+√3/2+1-√2/2+1
=3.
谢谢!
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