)如图,在等腰梯形ABCD中,AD‖BC,以A为圆心,AD为半径的圆与BC切于点M,与AB交于点E,若AD=2,BC=6,则弧DE的长为()连结AM,则AM⊥BC,∵四边形ABCD是等腰梯形∴BM=(BC-AD)÷2=2(就这里看不懂)又AM=CD=2.最
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![)如图,在等腰梯形ABCD中,AD‖BC,以A为圆心,AD为半径的圆与BC切于点M,与AB交于点E,若AD=2,BC=6,则弧DE的长为()连结AM,则AM⊥BC,∵四边形ABCD是等腰梯形∴BM=(BC-AD)÷2=2(就这里看不懂)又AM=CD=2.最](/uploads/image/z/2674457-17-7.jpg?t=%EF%BC%89%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E7%AD%89%E8%85%B0%E6%A2%AF%E5%BD%A2ABCD%E4%B8%AD%2CAD%E2%80%96BC%2C%E4%BB%A5A%E4%B8%BA%E5%9C%86%E5%BF%83%2CAD%E4%B8%BA%E5%8D%8A%E5%BE%84%E7%9A%84%E5%9C%86%E4%B8%8EBC%E5%88%87%E4%BA%8E%E7%82%B9M%2C%E4%B8%8EAB%E4%BA%A4%E4%BA%8E%E7%82%B9E%2C%E8%8B%A5AD%3D2%2CBC%3D6%2C%E5%88%99%E5%BC%A7DE%E7%9A%84%E9%95%BF%E4%B8%BA%EF%BC%88%EF%BC%89%E8%BF%9E%E7%BB%93AM%2C%E5%88%99AM%E2%8A%A5BC%2C%E2%88%B5%E5%9B%9B%E8%BE%B9%E5%BD%A2ABCD%E6%98%AF%E7%AD%89%E8%85%B0%E6%A2%AF%E5%BD%A2%E2%88%B4BM%3D%EF%BC%88BC-AD%29%C3%B72%3D2%EF%BC%88%E5%B0%B1%E8%BF%99%E9%87%8C%E7%9C%8B%E4%B8%8D%E6%87%82%EF%BC%89%E5%8F%88AM%3DCD%3D2.%E6%9C%80)
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