已知函数f(x)=根号3cos(2x-2派/3)+2sin^2(x-派/12),钝角三角形abc角a,b,c对边为a,b,c)的角满足f(B)=1.(1)求函数f(x)的单调递增区间.(2)若b=3,c=3√3,求B,a
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![已知函数f(x)=根号3cos(2x-2派/3)+2sin^2(x-派/12),钝角三角形abc角a,b,c对边为a,b,c)的角满足f(B)=1.(1)求函数f(x)的单调递增区间.(2)若b=3,c=3√3,求B,a](/uploads/image/z/2687182-70-2.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%3D%E6%A0%B9%E5%8F%B73cos%282x-2%E6%B4%BE%2F3%29%2B2sin%5E2%28x-%E6%B4%BE%2F12%29%2C%E9%92%9D%E8%A7%92%E4%B8%89%E8%A7%92%E5%BD%A2abc%E8%A7%92a%2Cb%2Cc%E5%AF%B9%E8%BE%B9%E4%B8%BAa%2Cb%2Cc%29%E7%9A%84%E8%A7%92%E6%BB%A1%E8%B6%B3f%28B%29%3D1.%281%29%E6%B1%82%E5%87%BD%E6%95%B0f%28x%29%E7%9A%84%E5%8D%95%E8%B0%83%E9%80%92%E5%A2%9E%E5%8C%BA%E9%97%B4.%282%29%E8%8B%A5b%3D3%2Cc%3D3%E2%88%9A3%2C%E6%B1%82B%2Ca)
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