(m2-2m+1)/(m2-1)÷((m-1)-(m-1)/(m+1)),其中m=根号3

来源:学生作业帮助网 编辑:作业帮 时间:2024/07/17 13:19:26
(m2-2m+1)/(m2-1)÷((m-1)-(m-1)/(m+1)),其中m=根号3
x)5566<tABt%A, yںɎ|ڿ&H*PEqAL&5@`ն`8#}0 )s jqGhCjrXp-Vu`)ū$@ h* saG k b+9O7l|۟jy>ɎgMO?ٽu:&$Acf񣧧͗O[Wl^tԧ{F@( T-ܟMbv2s> ,Nz.tr$%4

(m2-2m+1)/(m2-1)÷((m-1)-(m-1)/(m+1)),其中m=根号3
(m2-2m+1)/(m2-1)÷((m-1)-(m-1)/(m+1)),其中m=根号3

(m2-2m+1)/(m2-1)÷((m-1)-(m-1)/(m+1)),其中m=根号3
(m^2-2m+1)/(m^2-1)÷[(m-1)-(m-1)/(m+1)]
=(m-1)^2/(m-1)(m+1)÷[(m-1)(m+1)/(m+1)-(m-1)/(m+1)]
=(m-1)/(m+1)÷[(m^2-1)/(m+1)-(m-1)/(m+1)]
=(m-1)/(m+1)÷{[(m^2-1-(m-1)]/(m+1)}
=(m-1)/(m+1)÷{[m^2-1-m+1)]/(m+1)}
=(m-1)/(m+1)÷{[m^2-m)]/(m+1)}
=(m-1)/(m+1)÷{m(m-1)/(m+1)}
=(m-1)/(m+1)*(m+1)/[m(m-1)]
=1/m
=1/√3
=√3/3
就这样了,看不懂可以问我

(m^2-2m+1)/(m^2-1)÷[(m-1)-(m-1)/(m+1)]
=(m-1)^2/(m-1)(m+1)÷[(m-1)(m+1)/(m+1)-(m-1)/(m+1)]
=(m-1)/(m+1)÷[(m^2-1)/(m+1)-(m-1)/(m+1)]
=(m-1)/(m+1)÷{[(m^2-1-(m-1)]/(m+1)}
=(m-1)/(m+1)÷{[m^...

全部展开

(m^2-2m+1)/(m^2-1)÷[(m-1)-(m-1)/(m+1)]
=(m-1)^2/(m-1)(m+1)÷[(m-1)(m+1)/(m+1)-(m-1)/(m+1)]
=(m-1)/(m+1)÷[(m^2-1)/(m+1)-(m-1)/(m+1)]
=(m-1)/(m+1)÷{[(m^2-1-(m-1)]/(m+1)}
=(m-1)/(m+1)÷{[m^2-1-m+1)]/(m+1)}
=(m-1)/(m+1)÷{[m^2-m)]/(m+1)}
=(m-1)/(m+1)÷{m(m-1)/(m+1)}
=(m-1)/(m+1)*(m+1)/[m(m-1)]
=1/m
=1/√3
=√3/3

收起

条件不够吧