设a1=1,a2=5/3,a(n+2)=(5/3)[a(n+1)-(2/3)an(n=1,2,3…).(1)令bn=a(n+1)-an(n=1,2,…),求数列{bn}的通项公式;(2)求数列{nan}的前n项和Sn
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/13 03:08:25
![设a1=1,a2=5/3,a(n+2)=(5/3)[a(n+1)-(2/3)an(n=1,2,3…).(1)令bn=a(n+1)-an(n=1,2,…),求数列{bn}的通项公式;(2)求数列{nan}的前n项和Sn](/uploads/image/z/2729345-41-5.jpg?t=%E8%AE%BEa1%3D1%2Ca2%3D5%2F3%2Ca%28n%2B2%29%3D%285%2F3%29%5Ba%28n%2B1%29-%282%2F3%29an%28n%3D1%2C2%2C3%E2%80%A6%EF%BC%89.%281%29%E4%BB%A4bn%3Da%28n%2B1%29-an%28n%3D1%2C2%2C%E2%80%A6%EF%BC%89%2C%E6%B1%82%E6%95%B0%E5%88%97%7Bbn%7D%E7%9A%84%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F%EF%BC%9B%EF%BC%882%EF%BC%89%E6%B1%82%E6%95%B0%E5%88%97%7Bnan%7D%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8CSn)
xSJ@~ۋBE"QlE)Rh/ēު>t[{+8MI= 97|3SI
$;!>suБ X;Wu;{Ad(0`|2yRQNj3\Wht6(zW/PT9~$5lk`j4GJd{4&*@Za.5Ɔg߰EUJFpUܙ3&gUW6%B b,2
e/AH@ȇ+ij