1.如图,等腰梯形ABCD中,AD‖BC,AB=DC=5,AD=2,BC=8,∠MEN的顶点E在BC上移动,一条边始终经过点A,另一边与CD交于点F,使∠MEN=∠B,联接AE,若△AEF为等腰三角形(AF=EF),求BE的长2.已知AM‖BN,∠A=∠B=90°,AB=4,点
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![1.如图,等腰梯形ABCD中,AD‖BC,AB=DC=5,AD=2,BC=8,∠MEN的顶点E在BC上移动,一条边始终经过点A,另一边与CD交于点F,使∠MEN=∠B,联接AE,若△AEF为等腰三角形(AF=EF),求BE的长2.已知AM‖BN,∠A=∠B=90°,AB=4,点](/uploads/image/z/2731279-31-9.jpg?t=1.%E5%A6%82%E5%9B%BE%2C%E7%AD%89%E8%85%B0%E6%A2%AF%E5%BD%A2ABCD%E4%B8%AD%2CAD%E2%80%96BC%2CAB%3DDC%3D5%2CAD%3D2%2CBC%3D8%2C%E2%88%A0MEN%E7%9A%84%E9%A1%B6%E7%82%B9E%E5%9C%A8BC%E4%B8%8A%E7%A7%BB%E5%8A%A8%2C%E4%B8%80%E6%9D%A1%E8%BE%B9%E5%A7%8B%E7%BB%88%E7%BB%8F%E8%BF%87%E7%82%B9A%2C%E5%8F%A6%E4%B8%80%E8%BE%B9%E4%B8%8ECD%E4%BA%A4%E4%BA%8E%E7%82%B9F%2C%E4%BD%BF%E2%88%A0MEN%3D%E2%88%A0B%2C%E8%81%94%E6%8E%A5AE%2C%E8%8B%A5%E2%96%B3AEF%E4%B8%BA%E7%AD%89%E8%85%B0%E4%B8%89%E8%A7%92%E5%BD%A2%EF%BC%88AF%3DEF%EF%BC%89%2C%E6%B1%82BE%E7%9A%84%E9%95%BF2.%E5%B7%B2%E7%9F%A5AM%E2%80%96BN%2C%E2%88%A0A%3D%E2%88%A0B%3D90%C2%B0%2CAB%3D4%2C%E7%82%B9)
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