等比数列an中a3=7,前三项和s3=21,则公比q的值为多少,a3=a1*q^2=7; (1) s3=a1(1-q^3)/(1-q)=a1(1+q+q^2)=21; (2)(2)/(1)得 q=1,或q=-1/2;为什么a1(1-q^3)/(1-q)=a1(1+q+q^2)=21呢?

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等比数列an中a3=7,前三项和s3=21,则公比q的值为多少,a3=a1*q^2=7; (1) s3=a1(1-q^3)/(1-q)=a1(1+q+q^2)=21; (2)(2)/(1)得 q=1,或q=-1/2;为什么a1(1-q^3)/(1-q)=a1(1+q+q^2)=21呢?
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等比数列an中a3=7,前三项和s3=21,则公比q的值为多少,a3=a1*q^2=7; (1) s3=a1(1-q^3)/(1-q)=a1(1+q+q^2)=21; (2)(2)/(1)得 q=1,或q=-1/2;为什么a1(1-q^3)/(1-q)=a1(1+q+q^2)=21呢?
等比数列an中a3=7,前三项和s3=21,则公比q的值为多少,
a3=a1*q^2=7; (1)
s3=a1(1-q^3)/(1-q)=a1(1+q+q^2)=21; (2)
(2)/(1)得
q=1,或q=-1/2;
为什么a1(1-q^3)/(1-q)=a1(1+q+q^2)=21呢?

等比数列an中a3=7,前三项和s3=21,则公比q的值为多少,a3=a1*q^2=7; (1) s3=a1(1-q^3)/(1-q)=a1(1+q+q^2)=21; (2)(2)/(1)得 q=1,或q=-1/2;为什么a1(1-q^3)/(1-q)=a1(1+q+q^2)=21呢?
这是因式分解
1-q^3=(1-q)(1+q+q^2)