(求和)1/(1×2)+1/(2×3)+1/(3×4)+……+1/(2011×2012)
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/25 02:55:54
xP;0".pTLT03ӭ7AеWqR VJl?lP)sFXqSRUUaZȮ`an0bH3E+G?`l(vRQb<{/]\HAXإwjX?E+5{)D
r i?'$$¹WJ<#oR
(求和)1/(1×2)+1/(2×3)+1/(3×4)+……+1/(2011×2012)
(求和)1/(1×2)+1/(2×3)+1/(3×4)+……+1/(2011×2012)
(求和)1/(1×2)+1/(2×3)+1/(3×4)+……+1/(2011×2012)
1/2+1/6=2/3
1/2+1/6+1/12=3/4
1/2+1/6+1/12+1/20=4/5
.
所以
1/(1×2)+1/(2×3)+1/(3×4)+……+1/(2011×2012)
=2011/2012
2011/2012
1/(1×2)+1/(2×3)+1/(3×4)+……+1/(2011×2012)
=1-1/2+1/2-1/3+1/3-1/4+...+1/2011-1/2012
=1-1/2012
=2011/2012
2011/2012
1/n(n+1)=1/n-1/(n+1)
1/(1×2)+1/(2×3)+1/(3×4)+……+1/(2011×2012)
=1-1/2+1/2-1/3+1/3-1/4+...+1/2011-1/2012
=1-1/2012
=2011/2012
求和n^3/2^(n+1)求和RT
1/n(n+2)求和,求通项求和公式
1/(1+2+3+4+.+n)数列求和
数列求和 1+3+5+.+(2n-1)
求和:1+2+3+…+(n-1)的和
阶乘求和问题请问1!+2!+3!+.2007!怎么样求和?
数列(n^2)*(2n-1)求和
级数1/(n^2·(n+1)^2)求和
数列求和:1(1+1)+2(2+2).+n(n+1)
bn=(n/2+1/2)/2^n 求和
(a-1)+(a^2-2)+.+(a^n-n)求和
∑(2n+1)x^2n 求和函数
一道高中数学数列求和的题 求和:Sn=(1/1×3)+(4/3×5)+(9/5×7)+……+n的平方/(2n-1)(2n+1)
求和1+2×2+3×2∧2+……+(n+1)×2∧n
数列求和:(a+1) +( a2+2) +( a3+3)+…+ ( an+n)(a≠1)
求和:1+2x+3x²十…+nx∧(n-1)
极限求和Y=(-3)/((n+i)^2),当i属于1到n时,求和.(N—>正无穷)
关于等比数列求和.从a1求和到a(n-1)怎么算从a3求和到an怎么算