1、已知向量a=(2,2),向量b与向量a的夹角为3π/4,且a.b=-2(1)求向量b(2)若t=(1,0)且b⊥t,c=(cosa,2(cosc/2)^2),其中a、c是直角三角形的两个锐角,求|b+c|的值2、已知平面向量a=(根号3,-1),b=(1/2,
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![1、已知向量a=(2,2),向量b与向量a的夹角为3π/4,且a.b=-2(1)求向量b(2)若t=(1,0)且b⊥t,c=(cosa,2(cosc/2)^2),其中a、c是直角三角形的两个锐角,求|b+c|的值2、已知平面向量a=(根号3,-1),b=(1/2,](/uploads/image/z/2772319-31-9.jpg?t=1%E3%80%81%E5%B7%B2%E7%9F%A5%E5%90%91%E9%87%8Fa%3D%282%2C2%29%2C%E5%90%91%E9%87%8Fb%E4%B8%8E%E5%90%91%E9%87%8Fa%E7%9A%84%E5%A4%B9%E8%A7%92%E4%B8%BA3%CF%80%2F4%2C%E4%B8%94a.b%3D-2%EF%BC%881%EF%BC%89%E6%B1%82%E5%90%91%E9%87%8Fb%EF%BC%882%EF%BC%89%E8%8B%A5t%3D%EF%BC%881%2C0%EF%BC%89%E4%B8%94b%E2%8A%A5t%2Cc%3D%EF%BC%88cosa%2C2%28cosc%2F2%29%5E2%EF%BC%89%2C%E5%85%B6%E4%B8%ADa%E3%80%81c%E6%98%AF%E7%9B%B4%E8%A7%92%E4%B8%89%E8%A7%92%E5%BD%A2%E7%9A%84%E4%B8%A4%E4%B8%AA%E9%94%90%E8%A7%92%2C%E6%B1%82%7Cb%2Bc%7C%E7%9A%84%E5%80%BC2%E3%80%81%E5%B7%B2%E7%9F%A5%E5%B9%B3%E9%9D%A2%E5%90%91%E9%87%8Fa%3D%EF%BC%88%E6%A0%B9%E5%8F%B73%2C-1%EF%BC%89%2Cb%3D%EF%BC%881%2F2%2C)
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