limx→0(tanx-sinx)/[3^√(1+x^2))][√(1+sinx)-1]求极限_(:з」∠)_。分母是【三次根号下（1+x^2）】[√(1+sinx)-1]

limx->0[tanx-sinx]/sinx^3=? limx→0 tan(tanx)-sin(sinx)/x^3 limx→0 (tanx-sinx)/x limx→0 e^sinx(x-sinx)／(x-tanx) limx→0 (tanx-sinx)/sin^3x =limx→0 (tanx-sinx)/x³ 为什么可以直接去掉sinx limx→0 (tanx-sinx)/x求极限 求极限limx→0 tanx-sinx/xtanx∧2 求limX→0 (tanX-X)/(X-sinX) limx趋近于0 (tanx-sinx)/sin^3x limx趋近于0(sinx^3)tanx/1-cosx^2 limx→0(sinx^3tanx)/1-cosx^2等于多少,求详细 limx→0 (tanx-sinx)/[(2+x^2)^(1/2)]*{[e^(x^3）]-1}=? limx→0((✔1 tanx)-(✔sinx 1))/x^3求极限 limx->0 (x-xcosx) /(tanx-sinx)极限 limx→0{(tanx-x)/x^3} 求极限1.limx→-1(x^3+1)/sin(x+1); 2.limx→0(e^x-e^-x)/(sinx); 3.limx→+∞(ln(1+1/x))/(arccotx);4.limx→∞(tanx-sinx)/(1-cos2x); +tan(sinx)sin(tanx)什么意思limx→0+tan(sinx)sin(tanx)原式=limx→0+[sec(sinx)]^2cosx2tan(sinx)cos(tanx)sec2x2sin(tanx) （用罗比塔法则）=limx→0+sec2(sinx)cosxcos(tanx)sec2x•limx→0+sin(tanx)tan(sinx) （分离非零极限乘积 利用等价无穷小替换,求极限limx→0（tanx-sinx）/x^3 答案是1/2,